Search found 8 matches
Probability basics
If i have to chose two specific numbers from a set of 5 numbers:
Eg: 2 and 3 from set {1,2,3,4,5}
I understand the basic counting principle gives 2/5. (2 out of 5)
Using Combinations Will it be 2c2/5c2? or 2c2/5p2?
- by shashwats
Wed Jun 12, 2013 7:01 am- Forum: Problem Solving
- Topic: Probability basics
- Replies: 2
- Views: 1435
But does it not say "At least one of the colour and model" which means even RED and Large case should be included?
- by shashwats
Sun Jun 09, 2013 7:44 am- Forum: Problem Solving
- Topic: Some toys include large, middle, and small model with r
- Replies: 3
- Views: 2033
- by shashwats
Mon May 13, 2013 11:46 pm- Forum: Problem Solving
- Topic: Problem Solving
- Replies: 6
- Views: 1575
Problem Solving
Q:Each of the products produced yesterday was checked by x or y. 0.5% of the products checked by x are defective and 0.8% of the products checked by y are defective. If the total defective rate of all the products checked by x and y is 0.75%, what fraction of the products was checked by y?
- by shashwats
Mon May 13, 2013 11:12 pm- Forum: Problem Solving
- Topic: Problem Solving
- Replies: 6
- Views: 1575
Probability
If there are 10 balls, 3 red, 5 blue and 2 green. I pick two without replacement, what is the probability that both are red?
I find two ways of doing this, clearly one is wrong!
1) 3/10 * 2/9
2) (3C1 *2C1)/10C2
Can someone please help me understand this!
- by shashwats
Thu May 02, 2013 12:13 pm- Forum: Data Sufficiency
- Topic: Probability
- Replies: 3
- Views: 1229
- by shashwats
Mon Apr 29, 2013 6:31 am- Forum: Problem Solving
- Topic: Probability
- Replies: 9
- Views: 3285
Averages
A certain mixture of nuts consists of 4 parts almonds to 1 part walnuts, by weight. By removing some of the almonds, the remained nuts consist 75 percent of almonds, by weight. What percent of the almonds were removed?
(A) 10%
(B) 12.5%
(C) 20%
(D) 25%
(E) 30%
- by shashwats
Mon Apr 29, 2013 4:55 am- Forum: Problem Solving
- Topic: Averages
- Replies: 4
- Views: 1728
Probability
If 5 numbers are to be selected from integers from 1 to 20, inclusive, without replacement, what is the probability that both 5 and 15 will be selected?
(A) 1/57
(B) 1/19
(C) 3/19
(D) 4/57
(E) 2/19
What I thought of was:
(2C2 * 19C3)/ 21C5
- by shashwats
Mon Apr 29, 2013 4:43 am- Forum: Problem Solving
- Topic: Probability
- Replies: 9
- Views: 3285