Search found 34 matches
- by gamemaster
Wed Oct 04, 2006 4:55 am- Forum: Data Sufficiency
- Topic: Difficult Math Question #22 - Rates
- Replies: 10
- Views: 3735
a quick way to solve this, is like this: Lets say you have series of consequtive numbers: A1 A2 A3 A4 ..... An just to make things simple, lets say n is even (although it doesnt really matter) its obvious that A1 + An = A2 + An-1 = A3 + An-2 and so on ... this is the definition of arithmetic progres...
- by gamemaster
Sun Oct 01, 2006 11:21 am- Forum: Problem Solving
- Topic: Difficult math Q#1
- Replies: 3
- Views: 3897
you should define:
p - percent of discout for pony jeans
f - percent of discout for the fox jeans
now we know:
(1) f + p = 22
they say you save 9$ by buying 3 fox and 2 pony so:
(2) 3*(f/100)18 + 2*(p/100)15 = 9
solving these equations should give the answer ...
- by gamemaster
Thu Sep 28, 2006 1:16 am- Forum: Problem Solving
- Topic: question from disclosure 2
- Replies: 3
- Views: 2424
- by gamemaster
Thu Sep 28, 2006 1:08 am- Forum: Problem Solving
- Topic: question from disclosure
- Replies: 4
- Views: 3818
- by gamemaster
Wed Sep 27, 2006 1:58 am- Forum: Data Sufficiency
- Topic: Difficult Math Question #8
- Replies: 6
- Views: 5497
My solution: we have: 1 9 2 8 3 7 4 6 and also 0 and 5 so if we choose just one half of a pair (4 numbers for example 1,2,3,4) and 0 and 5, then only on the 7th number we'll succseed the answer will be 7 also if we look for combination of more than 2 numbers to sum up to 10, because we can choose: 9...
- by gamemaster
Tue Sep 26, 2006 11:35 pm- Forum: Problem Solving
- Topic: Difficult Math Question #21 - Probability
- Replies: 4
- Views: 2602
Yes
Although i admit this drawing is very confusing, i think it would be more practical to stick to the numbers in this question
- by gamemaster
Tue Sep 26, 2006 11:23 pm- Forum: Problem Solving
- Topic: easy question from disclosure
- Replies: 6
- Views: 3856
- by gamemaster
Tue Sep 26, 2006 12:46 pm- Forum: Problem Solving
- Topic: easy question from disclosure
- Replies: 6
- Views: 3856
The number of people that use A or B is: 400+400 - 200 = 600 but, from them we need to decrease another 100+125+75 = 300 people so we get 600-300 = 300 which are 30% from 1000 another way to solve it: people who use ONLY A = 400 - (125+75+125) = 75 people who use ONLY B = 400 - (125+75+100) = 100 pe...
- by gamemaster
Tue Sep 26, 2006 12:44 pm- Forum: Problem Solving
- Topic: easy question from disclosure
- Replies: 6
- Views: 3856
The expression in the multiple brackets equals eventually:
S = x+x^2+x^3+x^4+x^5
according to the question, An/S = x^5
=> An = x^6+x^7+x^8+x^9+x^10
so its easy to see n = 7
- by gamemaster
Fri Sep 22, 2006 1:05 pm- Forum: Problem Solving
- Topic: Difficult Math Question #19 - Difficult Alegbra
- Replies: 2
- Views: 3912
- by gamemaster
Thu Sep 21, 2006 1:27 am- Forum: Problem Solving
- Topic: Difficult Math Problem #17
- Replies: 6
- Views: 6613
My Answer
if the average of 7 sales is 400$, than in total he had to earn 2800$ in 7 sales
he made: 1000+700+250+200+100 = 2250$ in 5 sales
so in the the last 2 sales he had to make a comission of 550$
meaning he had to sell in an amount of 5500$
- by gamemaster
Thu Sep 21, 2006 12:46 am- Forum: Problem Solving
- Topic: Difficult Math Problem #17
- Replies: 6
- Views: 6613
.
clarification:
381/31 = 12 and a reminder of 9 (which are 9 minutes)
the local train drives at 50km/h so in 9 minutes it will pass:
(9/60)*50 = 7.5 km
- by gamemaster
Wed Sep 20, 2006 6:44 am- Forum: Problem Solving
- Topic: Difficult Math Problem #16
- Replies: 6
- Views: 13599
i ment 382/31 = 12 + 9 min
and (9/60)*50 = 7.5
so the answer is indeed: 307.5
final post from me on this thread 
- by gamemaster
Tue Sep 19, 2006 4:09 am- Forum: Problem Solving
- Topic: Difficult Math Problem #16
- Replies: 6
- Views: 13599
my suggestion
Total possibilites: 5! if i arrange couple A with single B like this: AAB then i can put couple C in the places marked by '_' : _A_A_B_ so ill have 4P2 = 12 options (A is man and female i assume :lol: so thats why it is 4P2) i can make 6 like this, so i have 72 options so total there are 72 options ...
- by gamemaster
Tue Sep 19, 2006 3:39 am- Forum: Problem Solving
- Topic: Difficult Math Problem #15
- Replies: 3
- Views: 4532