The expression in the multiple brackets equals eventually:
S = x+x^2+x^3+x^4+x^5
according to the question, An/S = x^5
=> An = x^6+x^7+x^8+x^9+x^10
so its easy to see n = 7
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Difficult Math Question #19 - Difficult Alegbra
Source: Beat The GMAT — Problem Solving |
here's the OA:
The method I followed was to reduce the Q to (x^6/ x ) * ( Y/Y)
the eqn An= (x ^ n -1)(1+ x + x^2 + x^3 +.... ) ----------------------------(1)
and the eqn x(1+x(1+x(1+x...))))
which I call Z can be reduced to x( 1+x+x^2+x^3 ..) --------(2)
from (1) and (2) we get An / Z = x^(n-1) / x
therefore for getting answer x^5 (n-1) = 6
therefore n=7
Ans: B
The method I followed was to reduce the Q to (x^6/ x ) * ( Y/Y)
the eqn An= (x ^ n -1)(1+ x + x^2 + x^3 +.... ) ----------------------------(1)
and the eqn x(1+x(1+x(1+x...))))
which I call Z can be reduced to x( 1+x+x^2+x^3 ..) --------(2)
from (1) and (2) we get An / Z = x^(n-1) / x
therefore for getting answer x^5 (n-1) = 6
therefore n=7
Ans: B
