Search found 42 matches
If 1 is in K, then 2 is in K. If 1 and 2 are in K, then 3 is in K. Therefore statement (1) implies statement (2).
Now, 1+1+...(15x) = 15 and 3+3+...(5x) = 15.
So either statement alone is sufficient to answer the question.
- by MM_Ed
Sat Jun 25, 2011 3:36 pm- Forum: Data Sufficiency
- Topic: BTG-PQ "K IS A SET OF INTEGERS SUCH THAT" ...
- Replies: 3
- Views: 2476
p: If t is in the set, t+2 is in the set.
q: If t+2 is in the set, t is in the set.
p does not imply q. You get 1 and 5 from p, but -3 from q. For all you know, -1 is the smallest number in the set : )
- by MM_Ed
Fri Jun 24, 2011 7:19 pm- Forum: Problem Solving
- Topic: Am I over considering all possibilities?
- Replies: 6
- Views: 862
- by MM_Ed
Fri Jun 24, 2011 6:52 pm- Forum: Sentence Correction
- Topic: Election time
- Replies: 91
- Views: 41855
2 + 4 + 6 +...+ 96 + 98 + 100
(adding 2 and 100, 4 and 98, etc. - 25 pairs)
= 102 + 102 + 102 +.... (25 times)
= 102*25
Isn't this essentially the same problem Gauss is said to have solved when he was ten? : )
- by MM_Ed
Wed Jun 22, 2011 8:32 pm- Forum: Problem Solving
- Topic: Sum of Even integers question, Gmat Hacks
- Replies: 6
- Views: 2107
Also, intuitively, x is the slowest, so x alone certainly can't takes less time than y and z combined.
- by MM_Ed
Tue Jun 21, 2011 4:34 pm- Forum: Problem Solving
- Topic: og math # 130
- Replies: 132
- Views: 58254
E, not D. It is the measure that is regarded as 'ineffective and meddlesome', &c., not the fight itself!
- by MM_Ed
Mon Jun 20, 2011 8:03 pm- Forum: Sentence Correction
- Topic: Speed limit - long one!
- Replies: 282
- Views: 109928
due to their differing velocities they slowly gain on or fall behind the disintegrating comet until a shroud of dust surrounds the entire cometary orbit The dust cloud is caused by an accumulation of particles ejected at various velocities. If they didn't have different velocities, the particles wo...
- by MM_Ed
Sun Jun 19, 2011 6:11 pm- Forum: Reading Comprehension
- Topic: OG10 - Astronomy related
- Replies: 6
- Views: 3675
Interesting question. It probably depends on one's learning style. I can use 3 languages confidently and yet entirely failed to pick up 2 others while living in cities where they were used widely (for 5 years each!) So being good at one language doesn't necessarily make one good at all others. Or ma...
- by MM_Ed
Sun Jun 19, 2011 5:45 pm- Forum: GMAT Verbal & Essays
- Topic: Good at one language--good at all languages?
- Replies: 4
- Views: 1911
Since the question implies that 1/3 like lima beans, the statements are equivalent. That means either i) each alone is sufficient to solve the problem or ii) the statements together are insufficient to solve the problem. Then try and solve the problem using either statement. If you can, it's i) and ...
- by MM_Ed
Sun Jun 19, 2011 5:31 pm- Forum: Data Sufficiency
- Topic: Gmat Prep Q
- Replies: 2
- Views: 902
If the defective (D) lights are found after exactly 3 trials, it means the 3rd one tried is defective. One of the first two tried is also defective, while the other is good (G). So the results are GDD or DGD. The number of permutations possible for three bulbs chosen out of 10 is 10x9x8 = 720. Since...
- by MM_Ed
Sun Jun 19, 2011 5:17 pm- Forum: GMAT Math
- Topic: Please help...stuck on these 2 probability questions
- Replies: 8
- Views: 2330
Let's say you do answer the first 10 incorrectly. Now you're writing the quant out of fifty. Even if you get everything else right, you're limiting your score at the very outset. Also, every other question will not be easy. Question 11 will be, then 12 will adapt to 11, and the last few questions wi...
- by MM_Ed
Sun Jun 19, 2011 5:00 pm- Forum: GMAT Math
- Topic: Is it good to purposely answer incorrectly at the beginning?
- Replies: 6
- Views: 4383
Only H = 10
Only F = 4
Only C = 6
HC (no F) = 5
HF (no C) = 3
CF (no H) = 2
HFC = 2
----
Total = 32
+ 18 non-players = 50
- by MM_Ed
Sun Jun 19, 2011 4:34 pm- Forum: GMAT Math
- Topic: Venn Diagram
- Replies: 20
- Views: 10315