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relation between x>y>z

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Re: relation between x>y>z

by Morgoth » Fri Sep 26, 2008 9:05 am
ifthyder wrote:how do we know about y ?
x>y>z ?

1) xz>yz, since x y and z are positive numbers we can simplify this
x>y. we dont know anything about z. Insufficient.

2) yx>yz, since x y and z are positive numbers we can simplify this
x>z, we dont know anything about y. Insufficient.

Combining 1 & 2

We still dont know about the relationship between z and y. Insufficient.

Thus, E is the answer.
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by kuroneko1313 » Fri Sep 26, 2008 10:46 am
I think it's E too, agree with Morgoth's explanation.
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by sumithshah » Tue Sep 30, 2008 10:02 am
Subtract 1 from 2, you shall get

xz-yx>0

x(z-y)>0

therefore, either both x and z-y>0 or x and z-y <0
but we know X>0 ( x is given as positive) hence z-y>0, z>y.

Hence C
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by EricLien9122 » Tue Sep 30, 2008 11:54 am
sumithshah:

I don't think you can subtract inequality equations.



Please share your thoughts.
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by gabriel » Tue Sep 30, 2008 1:40 pm
EricLien9122 wrote:sumithshah:

I don't think you can subtract inequality equations.



Please share your thoughts.
You can subtract inequality equations. But there are some operations like multiplication, division and squaring that you can do only after considering the sign of the variables in question.

Cheers.
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by schumi_gmat » Tue Sep 30, 2008 1:42 pm
what is the OA
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by kris610 » Wed Oct 01, 2008 11:58 am
sumithshah wrote:Subtract 1 from 2, you shall get

xz-yx>0

x(z-y)>0

therefore, either both x and z-y>0 or x and z-y <0
but we know X>0 ( x is given as positive) hence z-y>0, z>y.

Hence C
I can subract the other way around, in which case I would get y>z.

I think it is E.
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