BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Rectangular problem .

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Senior | Next Rank: 100 Posts
Posts: 32
Joined: Sat Jul 16, 2011 11:31 am
by Md.Nazrul Islam » Wed Apr 04, 2012 7:45 pm
The interior of a rectangular cartoon is designed by a certain manufacturer to have a volume of x cubic feet and a ratio of length to width to height is 3:2:2.In terms of 'x' what is the height of the cartoon in feet .
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3835
Joined: Fri Apr 02, 2010 10:00 pmFollowed by: 523 members
Location: Milpitas, CA
Thanked: 1854 times
GMAT Score:770

by Anurag@Gurome » Wed Apr 04, 2012 8:01 pm
Md.Nazrul Islam wrote:The interior of a rectangular cartoon is designed by a certain manufacturer to have a volume of x cubic feet and a ratio of length to width to height is 3:2:2.In terms of 'x' what is the height of the cartoon in feet .
Let us assume that the length = 3n, width = 2n and height = 2n
Then volume = length * width * height = 3n * 2n * 2n = 12(n^3) = x cubic ft
Solving 12(n^3) = x, we get
n^3 = x/12
n = (x/12)^(1/3)

Therefore, height of the carton = 2 * n = [spoiler]2 * (x/12)^(1/3)[/spoiler]
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Junior | Next Rank: 30 Posts
Posts: 15
Joined: Mon Mar 26, 2012 12:14 am
Thanked: 3 times

by gmatmath » Fri Apr 06, 2012 1:39 am
Given the ratio of length to width to height = 3:2:2.
so, Let the length'l' = 3k, width'w' = 2k and height'h' = 2k
Volume = lxwxh
x = 3k*2k*2k
x = 12k^3
==> k = (x/12)^(1/3)
so, height 'h' = 2k = 2[(x/12)^(1/3)
or h = two times the cuberoot of (x/12)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1