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rectangular crate

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Source: — Problem Solving |
GMAT Instructor
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by GMATDavid » Fri Sep 12, 2008 7:01 am
Hi,

The cylinder's volume is pi*r^2*h. There are 3 ways to lay the crate: with the 8x10 side down, with the 8x12 side down or with the 10x12 side down.

Whether the 8x10 side or the 8x12 side is down, the maximum radius would be 4 feet (diameter 8 feet), so the 8x12 would give a larger height and larger volume..

With the 10x12 side down, the radius would have to be 5 (diameter 10).

Thus, the question is: would a cylinder with a radaius of 5 and a height of 8 have a greater volume or would the cylinder with a radius of 4 and a height of 12 have the greater volume. The pis cancel out, of course. 5^2*8 is 200. 4^2*12 is only 192.

Cheers,
David Stoll
The Princeton Review
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