## Ratios fun

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### Ratios fun

by mjjking » Tue Mar 24, 2009 11:36 pm
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by NethraN » Wed Mar 25, 2009 2:17 am
given W/C = 5/2 so C = 2W/5

stmt 1) says C/M = 5/11 => C = 5M/11

2W/5 = 5M/11 => M= 22W/25 Not Sufficient

stmt 2) W < 30 Not Sufficient

Both stmts together are sufficient

we know M = 22W/25 and M and W has to be a whole numbers the only number below 30 that is divisible by 25 is 25 so W = 25 hence M = 22

Nethra

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by Tryingmybest » Wed Mar 25, 2009 9:43 am
IMO A

Given
W: c = 5 : 2 = 25: 10

From A
c: m = 5 : 11 = 10 : 22

So w: c:m = 25: 10: 22 which cannot be minimized further

So no . of men = 22

A

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by lilu » Wed Mar 25, 2009 10:18 am
The first Statement gives us the proportion of m to c AND to W, but no number limits
The second Statement gives us the number limit of up to 30.

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by Tryingmybest » Wed Mar 25, 2009 11:41 am
Yes indeed

We reach a Proportion 25 : 10 : 22 which cannot be divided further . So there has to be 22 men. we get this info from A .. The information given B is not required to arrive at this conclusion

Any Inputs on this???

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by moutar » Wed Mar 25, 2009 12:31 pm
[quote="Tryingmybest"]Yes indeed

We reach a Proportion 25 : 10 : 22 which cannot be divided further . So there has to be 22 men. we get this info from A .. The information given B is not required to arrive at this conclusion

Any Inputs on this???[/quote]

But there could be 44 men.

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by Tryingmybest » Wed Mar 25, 2009 1:49 pm
Sorry .. Thanks for Pointing that out.

It must be C

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by mjjking » Fri Mar 27, 2009 1:30 am
thanks guys for the explanations! Makes sense now!!
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### Re: Ratios fun

by Vemuri » Fri Mar 27, 2009 5:30 am
What is a Data Sufficiency question doing in Problem Solving section? I am sure you must have posted unintentionally

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