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Ratio

Expert replies
by shashank.ism » Sat Feb 20, 2010 12:20 pm
A square and a regular hexagon have same area A . Find the ratio of the perimeter of the square to the perimeter of the hexagon.
A) sqrt3 :2
B) 1 : 2
C) 3^(1/4) : 4^(1/4)
D) 4^(1/4) : 3^(1/4)
E) None
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Source: — Problem Solving |

by gmattarget700 » Sat Feb 20, 2010 1:50 pm
to me it seems answer is E

assuming square side = a, Hexagon size = b

a^2 = (3 * sqrt 3)/2 * b^2

=> 4a/6b = 2/3 * sqrt [ (3* sqrt 3) /2)]
or can be put this way: 4a/6b = (sqrt 2)/ 3 * [sqrt ( 3 * sqrt 3)]


its not matching with option A, B, C..

OR, am i doing something wrong? :)
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by gmattarget700 » Sun Feb 21, 2010 12:18 am
any other thoughts??
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by shashank.ism » Sun Feb 21, 2010 12:50 am
OA is D ..
Area of regular hexagon of side a= 6x sqrt3 /4 x a^2
Area of square of side b = b^2
6x sqrt3 /4 x a^2 = b^2
b/a = [3)^(3/4) ]/sqrt 2
ratio of perimeter of square to hexagon = 4b/6a = 4/6 x[[3)^(3/4) ]/sqrt 2] =[spoiler] (4/3)^(1/4) Ans D[/spoiler]
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by harsh.champ » Sun Feb 21, 2010 2:29 am
gmattarget700 wrote:to me it seems answer is E

assuming square side = a, Hexagon size = b

a^2 = (3 * sqrt 3)/2 * b^2

=> 4a/6b = 2/3 * sqrt [ (3* sqrt 3) /2)]
or can be put this way: 4a/6b = (sqrt 2)/ 3 * [sqrt ( 3 * sqrt 3)]


its not matching with option A, B, C..

OR, am i doing something wrong? :)
Hey gmattarget700,
This is what you have written:-
4a/6b = 2/3 * sqrt [ (3* sqrt 3) /2)]
Now look carefully at the answer choices:-They are only given to confuse you.
I will explain step-by-step
2/3 * sqrt [ (3* sqrt 3) /2) can be written as (2/3)[(3^1/2)(3^1/4)/(2^1/2)]
Cancelling the exponents of 2 and 3 in Dr. and Nr.respectively ,
=>(2^1/2)/(3^1/4)
Now 2=4^1/2
Hence we get [(4^1/2)^1/2}/(3^1/4)
which is equal to (4^1/4)/(3^1/4)
which is C.

I hope the explanation helps.
It takes time and effort to explain, so if my comment helped you please press Thanks button :)



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by gmattarget700 » Sun Feb 21, 2010 2:40 am
I realized that after seeing the OA.... looking at None choice made me jump to decide on it faster.....yeah, need to be more careful...as it clearly shows that even if you have done right calculation and have right answer, you may not pick the right choice :)

thanks anyway, for your better explanation...
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by shashank.ism » Sun Feb 21, 2010 5:52 am
yeah u did some mistake in between and thats why u went far away from ans...
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by gmattarget700 » Sun Feb 21, 2010 9:58 am
I am interested to know which " some mistake in between" i did, as you mentioned....I had deduced the RIGHT answer (4a/6b = 2/3 * sqrt [ (3* sqrt 3) /2)]...Harsh also quoted that) but it needed some "massaging" to map with right choice but I didn't have patience to do that massaging and so wrongly chose E.

so tell me which mistake you are referring??
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by shashank.ism » Sun Feb 21, 2010 12:32 pm
gmattarget700 wrote:I am interested to know which " some mistake in between" i did, as you mentioned....I had deduced the RIGHT answer (4a/6b = 2/3 * sqrt [ (3* sqrt 3) /2)]...Harsh also quoted that) but it needed some "massaging" to map with right choice but I didn't have patience to do that massaging and so wrongly chose E.

so tell me which mistake you are referring??
I was saying about the same gmattarget 700..... well u have corrected it now...
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