rate-work -any short method

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rate-work -any short method

by hey_thr67 » Mon Jun 25, 2012 9:38 am
Machine A can complete a certain job in x hours. Machine B can complete the same job in y hours. If A and B work together at their respective rates to complete the job, which of the following represents the fraction of the job that B will not have to complete?

A:
x - y
------
x + y

B:
x
-----
y - x

C:
x + y
-----
xy

D:

y
-----
x - y

E:
y
----
x + y

OA is E

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by eagleeye » Mon Jun 25, 2012 9:50 am
Hi hey_thr67:

The key to doing this fast is realizing that as long as A and B works at their constant rates, the fraction of work done by A and B in any given time is the same. With that in mind, let's do this one quickly.

Machine A can complete a certain job in x hours.
Hence, work done by A in one hour = 1/x.

Machine B can complete the same job in y hours.
Hence, work done by B in one hour = 1/y.

When they are working together work done by A and B in one hour = 1/x+1/y.

Now the work that B doesn't do, is the work that is done by A. Hence the correct fraction of work done by A
= (work done by A in one hour) / (Work done by A and B together in 1 hour)
= (1/x) / (1/x+1/y) = xy/( x*(x+y)) = y/(x+y). Hence E

Let me know if this helps :)

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by Anurag@Gurome » Mon Jun 25, 2012 9:51 am
hey_thr67 wrote:Machine A can complete a certain job in x hours. Machine B can complete the same job in y hours. If A and B work together at their respective rates to complete the job, which of the following represents the fraction of the job that B will not have to complete?
Fraction of the job that B will not have to complete = Fraction of the job that A will complete

Algebraic Approach:
In 1 hour, A completes 1/x of the job.
In 1 hour, B completes 1/y of the job.
In 1 hour, A and B together complete (1/x + 1/y) = (x + y)/xy of the job.

Hence, A and B together will complete the job in xy/(x + y) hours.
In xy/(x + y) hours A will do [xy/(x + y)]*(1/x) = y/(x + y) of the job.

The correct answer is E.
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by Anurag@Gurome » Mon Jun 25, 2012 10:00 am
hey_thr67 wrote:Machine A can complete a certain job in x hours. Machine B can complete the same job in y hours. If A and B work together at their respective rates to complete the job, which of the following represents the fraction of the job that B will not have to complete?
Fraction of the job that B will not have to complete = Fraction of the job that A will complete

Tricky Approach:
Let us assume that A completes the job in zero hours, i.e. A completes the job alone and we don't need B to any part of the job. (This is not practically impossible but mathematics should hold for this situation also)

Hence, x = 0
We will put this value of x in the given options to see which of them is equal to 1.
  • A. (x - y)/(x + y) = -y/y = -1 --> NO
    B. x/(x + y) = 0 --> NO
    C. (x + y)/(xy) = Not definite --> NO
    D. y/(x - y) = -y/y = -1 --> NO
    E. y/(x + y) = y/y = 1 --> YES
The correct answer is E.
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by GMATGuruNY » Mon Jun 25, 2012 10:28 am
hey_thr67 wrote:Machine A can complete a certain job in x hours. Machine B can complete the same job in y hours. If A and B work together at their respective rates to complete the job, which of the following represents the fraction of the job that B will not have to complete?

A:
x - y
------
x + y

B:
x
-----
y - x

C:
x + y
-----
xy

D:

y
-----
x - y

E:
y
----
x + y

OA is E
Time and rate are RECIPROCALS.
Let x = 2 hours and y = 5 hours.
Since the ratio of A's time to B's time = 2:5, the ratio of A's rate to B's rate = 5:2.
The ratio of the rates implies the following:
Of every 7 units produced, 5 will be produced by A and 2 will be produced by B, implying that the fraction not produced by B = 5/7. This is our target.
Now we plug x=2 and y=5 into the answers to which yields our target of 5/7.
A quick scan of the answer choices reveals that only E works:
y/(x+y) = 5/(2+5) = 5/7.

The correct answer is E.

Note that the same reasoning can be applied directly to the variables themselves.
Since the ratio of A's time to B's time = x:y, the ratio of A's rate to B's rate = y : x.
The ratio of the rates implies the following:
Of every (x+y) units produced, y will be produced by A, implying that the fraction not produced by B = y/(x+y).
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