BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Rate problem

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Senior | Next Rank: 100 Posts
Posts: 46
Joined: Fri Aug 19, 2011 12:13 amFollowed by: 1 member
Location: Delhi, India
by romitvsingh » Mon Dec 05, 2011 11:18 pm
While on a straight road, car X & car Y are travelling at different constant rates. If car X is now 1 mile ahead of car Y, how many minutes from now will car X be 2 miles ahead of car Y?

1) Car X is travelling at 50 miles per hour and car Y is travelling at 40 miles per hour.

2) Three minutes ago car X was 1/2 miles ahead of car Y

Pls explain in detail
Eat, sleep GMAT
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Data Sufficiency |
Master | Next Rank: 500 Posts
Posts: 218
Joined: Wed Nov 23, 2011 8:05 pmFollowed by: 4 members
Thanked: 26 times

by chieftang » Mon Dec 05, 2011 11:33 pm
Each statement is sufficient.

1. Every 6 minutes the cars are 1 mile further apart. 12 minutes = 2 miles apart.

2. If 3 minutes = 0.5 miles, then X minutes = 2 miles. X = 12.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3835
Joined: Fri Apr 02, 2010 10:00 pmFollowed by: 523 members
Location: Milpitas, CA
Thanked: 1854 times
GMAT Score:770

by Anurag@Gurome » Mon Dec 05, 2011 11:34 pm
romitvsingh wrote:While on a straight road, car X & car Y are travelling at different constant rates. If car X is now 1 mile ahead of car Y, how many minutes from now will car X be 2 miles ahead of car Y?

1) Car X is travelling at 50 miles per hour and car Y is travelling at 40 miles per hour.

2) Three minutes ago car X was 1/2 miles ahead of car Y

Pls explain in detail
(1) As the cars are moving in the same direction, relative speed of the cars = (50 - 40) = 10 miles per hour.

Total distance between them cover = (2 - 1) = 1 mile

Hence, time required = 1/10 hour = 6 minutes; SUFFICIENT.

(2) In three minutes, car X is (1 - 1/2) = 1/2 miles ahead of car Y.
Hence, relative speed of the cars = 1/2 miles per 3 minute = 1 mile per 6 minute

Total distance between them cover = (2 - 1) = 1 mile

Hence, time required = 6 minutes; SUFFICIENT.

The correct answer is D.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 102
Joined: Thu Jul 21, 2011 2:22 amFollowed by: 1 member
Location: Lahore, Pakistan
Thanked: 4 times

by chufus » Tue Dec 06, 2011 3:37 am
A.

Car X travels 50/60 = 5/6 miles per minute
Car Y travels 40/60 = 4/6 miles per minute

Distance travelled by X = x
Distance travelled by Y = x-1

Time taken by both is the same.

Time is distance/speed

so x/(5/6) = x-1/(4/6)

Solve to find x = 5 miles

Distance is 5 miles, speed is 5/6 miles per minute

So > 5(5/6) = 6 minutes

SUFFICIENT

B. 3 minutes ago they were 1/2 miles apart and now they are 1 mile apart. So X gains half a mile every 3 minutes since they are at constant speed.

Hence to add a mile would take 3*2 = 6 Minutes

SUFFICIENT

Pick "D"[/b]
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1