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by sgr21 » Fri Dec 06, 2013 12:41 am
annie and stephanie are running a 5000 meters race,anne finishes the race 40s before stephanie,if it is known that stephanies speed while running was 25m/s. what was annies speed?

A 20 M/S
B 28.75 M/S
C 31.25 M/S
D 34.50 M/S
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by theCodeToGMAT » Fri Dec 06, 2013 2:14 am
Distance = 5000

Time of A = TIme of S - 40s

5000/A = 5000/25 - 40

5000/A = 200 - 40

5000/A = 160

A = 5000/160 = 31.25
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by GMATGuruNY » Fri Dec 06, 2013 4:03 am
sgr21 wrote:annie and stephanie are running a 5000 meters race,anne finishes the race 40s before stephanie,if it is known that stephanies speed while running was 25m/s. what was annies speed?

A 20 M/S
B 28.75 M/S
C 31.25 M/S
D 34.50 M/S
Stephanie's time = d/r = 5000/25 = 200 seconds.
Since Annie finishes 40 seconds earlier, Annie's time = 200-40 = 160 seconds.
Thus, Annie's rate = d/t = 5000/160 = 125/4 = 31.25 meters per second.

The correct answer is C.
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by Brent@GMATPrepNow » Fri Dec 06, 2013 6:20 am
The solutions that Mitch and theCodeToGMAT provided are great.
I just thought I'd mention that, once you get the point where you know the answer is 125/4, you can quickly find the correct answer by first recognizing that, since 120/4 = 30, 125/4 must be GREATER than 30.
So, we can ELIMINATE A and B
Next recognize that any odd integer divided by 4 always ends with either .25 or .75
This means we can ELIMINATE D, to get C as the correct answer.

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by Mathsbuddy » Fri Dec 06, 2013 7:35 am
In agreement with the other responders, here's a speed-time graph to help illustrate the solution.
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by Mathsbuddy » Fri Dec 06, 2013 7:36 am
Duplicate message. Please delete.
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