annie and stephanie are running a 5000 meters race,anne finishes the race 40s before stephanie,if it is known that stephanies speed while running was 25m/s. what was annies speed?
A 20 M/S
B 28.75 M/S
C 31.25 M/S
D 34.50 M/S
race
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- theCodeToGMAT
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Distance = 5000
Time of A = TIme of S - 40s
5000/A = 5000/25 - 40
5000/A = 200 - 40
5000/A = 160
A = 5000/160 = 31.25
Time of A = TIme of S - 40s
5000/A = 5000/25 - 40
5000/A = 200 - 40
5000/A = 160
A = 5000/160 = 31.25
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Stephanie's time = d/r = 5000/25 = 200 seconds.sgr21 wrote:annie and stephanie are running a 5000 meters race,anne finishes the race 40s before stephanie,if it is known that stephanies speed while running was 25m/s. what was annies speed?
A 20 M/S
B 28.75 M/S
C 31.25 M/S
D 34.50 M/S
Since Annie finishes 40 seconds earlier, Annie's time = 200-40 = 160 seconds.
Thus, Annie's rate = d/t = 5000/160 = 125/4 = 31.25 meters per second.
The correct answer is C.
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My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
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- Brent@GMATPrepNow
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The solutions that Mitch and theCodeToGMAT provided are great.
I just thought I'd mention that, once you get the point where you know the answer is 125/4, you can quickly find the correct answer by first recognizing that, since 120/4 = 30, 125/4 must be GREATER than 30.
So, we can ELIMINATE A and B
Next recognize that any odd integer divided by 4 always ends with either .25 or .75
This means we can ELIMINATE D, to get C as the correct answer.
Cheers,
Brent
I just thought I'd mention that, once you get the point where you know the answer is 125/4, you can quickly find the correct answer by first recognizing that, since 120/4 = 30, 125/4 must be GREATER than 30.
So, we can ELIMINATE A and B
Next recognize that any odd integer divided by 4 always ends with either .25 or .75
This means we can ELIMINATE D, to get C as the correct answer.
Cheers,
Brent
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In agreement with the other responders, here's a speed-time graph to help illustrate the solution.
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