If x and y are integers and 2x-y= 11, then 4x+ y CANNOT be
(A) -5(B) 1(C) 13(D) 17(E) 55
PS - Integers
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- karthikpandian19
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2x - y = 11karthikpandian19 wrote:If x and y are integers and 2x-y= 11, then 4x+ y CANNOT be
(A) -5(B) 1(C) 13(D) 17(E) 55
4x - 2y = 22
4x + y = 3y + 22, which can be written as 3(y + 7) + 1
When we subtract 1 from 4x + y then it will be a multiple of 3.
Only 17 - 1 = 16, which is not a multiple of 3.
The correct answer is D.
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solving with simultaneous equations will also give a solution!!!
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2x-y=11 multiply this equation by 2karthikpandian19 wrote:If x and y are integers and 2x-y= 11, then 4x+ y CANNOT be
(A) -5(B) 1(C) 13(D) 17(E) 55
4x-2y=22
so, now we have
4x-2y=22
minus
4x+y=Z
--------------
-3y=22-z
(A) -5 ; -3y=22+5 y is an integer. eliminate A
(B) 1; -3y=22-1 y is an integer .eliminate B
(C) 13; -3y=22-13 y is an integer .eliminate C
(D) 17; -3y=22-17 . y=5/3 .so y is not an integer. D is correct
(E) 55; -3y=22-55 y is an 326integer. eliminate E
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D is the correct answer.So it's easy question .how do you do ratios to solve problem related to it .Thanks .