If the operation ◙ is defined for all a and b by the
equation a ◙ b = 3
a2b , then 2 ◙ (3 ◙ – 1) =
(A)4
(B)2
C)-4/3
(D)– 2
(E)– 4
equation a ◙ b = 3
a2b , then 2 ◙ (3 ◙ – 1) =
(A)4
(B)2
C)-4/3
(D)– 2
(E)– 4
Last edited by barira1 on Thu Jan 21, 2010 4:32 am, edited 1 time in total.
