six cards are numbered 1 to 6.with replacement one card is drawn out at random four times. If the products of numbers in the card is 120 , what is the probability that all the four nos are different from each other.
a) 1/3
b) 2/3
c) 4/5
d) 1/2
e) 1/5
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probability
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tohellandback
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is it B- 2/3
120=2*2*2*3*5
cards are 1 2 3 4 5 6
we need a 5, a 3, and 3 2's
our options are
3 5 2 4
6 5 2 2
6 5 4 1
probability of getting 3524 or 6541 is 2/3
120=2*2*2*3*5
cards are 1 2 3 4 5 6
we need a 5, a 3, and 3 2's
our options are
3 5 2 4
6 5 2 2
6 5 4 1
probability of getting 3524 or 6541 is 2/3
The powers of two are bloody impolite!!
