As part of a game, four people each must secretly choose an integer between 1 and 4, inclusive. What is the approximate likelihood that all four people will choose different numbers ?
a) 9%
b) 12%
c) 16%
d) 20%
e) 25%
Please help me with this problem.
OA A
5-Day Free Trial
5-day free, full-access trial TTP
Available with Beat the GMAT members only code
MORE DETAILS
Probability Problem
This topic has expert replies
-
sands_of_time
- Junior | Next Rank: 30 Posts
- Posts: 21
- Joined: Tue Apr 07, 2009 4:47 am
possibility of all the 4 choose different nos(event) : 4 * 3 * 2 * 1
possibility of all the 4 choose any no. (sample space) : 4 * 4 * 4 * 4
answer choices are in % so multiply event/SS by 100 to get the approximate answer.
possibility of all the 4 choose any no. (sample space) : 4 * 4 * 4 * 4
answer choices are in % so multiply event/SS by 100 to get the approximate answer.
-
bluementor
- Master | Next Rank: 500 Posts
- Posts: 418
- Joined: Wed Jun 11, 2008 5:29 am
- Thanked: 65 times
No. of ways 4 people can choose 4 integers = 4x4x4x4
No. of ways 4 people can choose different integers = 4x3x2x1
Prob of 4 people choosing different integers =
(4x3x2x1)/(4x4x4x4) = 3/32 ≈ 9%
Choose A.
-BM-
No. of ways 4 people can choose different integers = 4x3x2x1
Prob of 4 people choosing different integers =
(4x3x2x1)/(4x4x4x4) = 3/32 ≈ 9%
Choose A.
-BM-
