Hi All, easy but I stuck on it !
A certain compagny employs 6 senior officers and 4 junior officers. If a comitee is to be created that is made up of 3 senior officers and 1 junior officer, How many different committees are possible?
* 8
* 24
* 58
* 80 ( That was the right answer )
* 210
Thanks
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Uri
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It seems the problem is not reproduced correctly.
You can select 6 senior officers from 6 senior officers in only 1 way. And you can pick 1 junior officer from 4 junior officers in 4 ways. For each of the way that you pick a junior officer, you have only one combination of senior officers. So, the total combination will be 4*1 = 4.
Am I missing any point?
You can select 6 senior officers from 6 senior officers in only 1 way. And you can pick 1 junior officer from 4 junior officers in 4 ways. For each of the way that you pick a junior officer, you have only one combination of senior officers. So, the total combination will be 4*1 = 4.
Am I missing any point?
I think there might be some mistake in the question. If not then the number of ways a committe can be formed with 6Seniors and 1 Junior is 4 ways.
This is becuase, for each combination, all the 6 Senior will be picked. And amoung 4 Juniors, there are 4 ways we can pick one junior.
This is becuase, for each combination, all the 6 Senior will be picked. And amoung 4 Juniors, there are 4 ways we can pick one junior.
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gaggleofgirls
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Given that the right answer is 80, I am guessing that the correct question is a committee of 3 senior officers and 1 junior officer.
That would be 6c3 * 4c1 = 20*4 = 80.
-Carrie
That would be 6c3 * 4c1 = 20*4 = 80.
-Carrie
