If there are 400 women at College X and 200
students live off-campus, how many students
does College X have?
(1) 120 women live off-campus.
(2) There are half as many men at College X as
there are students who live on-campus.
Does anyone know the ans to this problem?
Princeton hard math - set1- q 6
This topic has expert replies
-
- Newbie | Next Rank: 10 Posts
- Posts: 5
- Joined: Fri Feb 01, 2008 8:37 pm
If there are 400 women at College X and 200
students live off-campus, how many students
does College X have?
(1) 120 women live off-campus.
(2) There are half as many men at College X as
there are students who live on-campus.
ans- at college; 400-women, men-?
outside- 120- women, men?
so stst 1 is not sufficient
st2 let num of men in campus be x, then (400 + x)/2 = x
x= 400. hence total = 400+400+200=1000.
st 2 is sufficient.
i hope this makes u comfortable. if u find sth esoteric do reply to me.
cheers
![Rolling on the Floor Laughing :lol:](./images/smilies/lol.png)
students live off-campus, how many students
does College X have?
(1) 120 women live off-campus.
(2) There are half as many men at College X as
there are students who live on-campus.
ans- at college; 400-women, men-?
outside- 120- women, men?
so stst 1 is not sufficient
st2 let num of men in campus be x, then (400 + x)/2 = x
x= 400. hence total = 400+400+200=1000.
st 2 is sufficient.
i hope this makes u comfortable. if u find sth esoteric do reply to me.
cheers
![Rolling on the Floor Laughing :lol:](./images/smilies/lol.png)
![Rolling on the Floor Laughing :lol:](./images/smilies/lol.png)
![Rolling on the Floor Laughing :lol:](./images/smilies/lol.png)
![Rolling on the Floor Laughing :lol:](./images/smilies/lol.png)
-
- Senior | Next Rank: 100 Posts
- Posts: 62
- Joined: Tue Jan 16, 2007 9:40 am
- Location: Arlington,VA
how do u decide how many students live ON CAMPUS?
There is no Mention of the number of students who live on campus...
I would have to go with E.
The closest match is I can get to 280 women on campus and 120 off campus.
that leave me with 80 men off campus . Still no information on how many male students live on campus.
Does it make any sense ?
There is no Mention of the number of students who live on campus...
I would have to go with E.
The closest match is I can get to 280 women on campus and 120 off campus.
that leave me with 80 men off campus . Still no information on how many male students live on campus.
Does it make any sense ?
Answer should be C.Nidhs wrote:If there are 400 women at College X and 200
students live off-campus, how many students
does College X have?
(1) 120 women live off-campus.
(2) There are half as many men at College X as
there are students who live on-campus.
Does anyone know the ans to this problem?
(1) and (2) alone does not converge to any answer. Lets check them together.
Data: 400 women, 200 off campus student (men+women), 120 women off campus so
200-120=80 men off campus
400-120 = 280 women on-campus
say the number of men student living on campus is M. Then 280+M women and men lives on campus
(2) says that M+80 = (280+M)/2. Solve for M. M = 120
So # of students are 400 women +200 men = 600
Probelm solved. Answer is C.
Last edited by arawamis on Sun Feb 10, 2008 9:32 am, edited 1 time in total.
-
- Newbie | Next Rank: 10 Posts
- Posts: 2
- Joined: Sat Feb 09, 2008 5:25 pm
- Location: Memphis
- Thanked: 1 times
I think Cluvaduva wrote:I think it is E as well.
Anyone else?
Stmt 1 provides number of women on campus 400-120=280
Stmt 2 provides that total on campus is 2 times number of men
x=number of men
x-80 = number of men on campus
number of men on campus (x-80)
plus number of women on campus (280)
= twice the number of men (2x)
x-80+280=2x
x=200
------------off-----on----Total
men-------80----120----200
women---120---280----400
TOTAL----200---400----600
-
- Senior | Next Rank: 100 Posts
- Posts: 69
- Joined: Sun Jan 06, 2008 7:12 pm
- Thanked: 3 times
- Followed by:1 members
i still think u can get the same ans by using only st2
consider the table below
The question stem provides us with the foll
------- M-------- W
C ------------------
OC ------------------- 200
---------------- 400
Now st2 tells us that
There are half as many men at College X as there are students who live on-campus.
Therefore
------- M----------W
C ------------------------ 2x
OC ---------------------- 200
------- x -------- 400-------
2x+200=x+400
x=200
Total no of students is 600.
Any inputs?
consider the table below
The question stem provides us with the foll
------- M-------- W
C ------------------
OC ------------------- 200
---------------- 400
Now st2 tells us that
There are half as many men at College X as there are students who live on-campus.
Therefore
------- M----------W
C ------------------------ 2x
OC ---------------------- 200
------- x -------- 400-------
2x+200=x+400
x=200
Total no of students is 600.
Any inputs?
-
- Junior | Next Rank: 30 Posts
- Posts: 16
- Joined: Tue Feb 05, 2008 10:47 am
- Thanked: 3 times
I agree with Nidhs. Because, Students on Campus + Out of campus = men + women, which is the same as 400+x=2x+200
Stuart, what's our mistake???
Stuart, what's our mistake???
T minus 17 hours
- Stuart@KaplanGMAT
- GMAT Instructor
- Posts: 3225
- Joined: Tue Jan 08, 2008 2:40 pm
- Location: Toronto
- Thanked: 1710 times
- Followed by:614 members
- GMAT Score:800
From the original we know that there are 400 women and 200 off campus students. We want to know the total # of students.Nidhs wrote:If there are 400 women at College X and 200
students live off-campus, how many students
does College X have?
(1) 120 women live off-campus.
(2) There are half as many men at College X as
there are students who live on-campus.
Does anyone know the ans to this problem?
So, if we know either the total # of men OR the total # of on-campus students, we can solve.
(1) 120 women live off campus - gives us neither piece of info we need.
(2) #men = 1/2 the # of on campus. Since we don't know either of these variables, we can't solve for the other. Not good enough by itself.
Combined:
(1) tells us that there are 280 women who live on campus. When we combine this with (2) we get 2 equations:
M = 1/2 (OnCamp)
and M = OnCamp - 280
Now we have 2 equations and 2 unknowns, we can solve for M (and since we know W, we can answer the question): choose (C).
![Image](https://i.imgur.com/YCxbQ7s.png)
Stuart Kovinsky | Kaplan GMAT Faculty | Toronto
Kaplan Exclusive: The Official Test Day Experience | Ready to Take a Free Practice Test? | Kaplan/Beat the GMAT Member Discount
BTG100 for $100 off a full course
- Stuart@KaplanGMAT
- GMAT Instructor
- Posts: 3225
- Joined: Tue Jan 08, 2008 2:40 pm
- Location: Toronto
- Thanked: 1710 times
- Followed by:614 members
- GMAT Score:800
Hmm.. maybe I'll change my mind on this question!davidforsberg wrote:I agree with Nidhs. Because, Students on Campus + Out of campus = men + women, which is the same as 400+x=2x+200
Stuart, what's our mistake???
We do know that w + m = on + off
w=400
off = 200
on = 2m
4 equations, 4 unknowns - we should be able to solve for everything.
400 + m = 2m + 200
200 = m
So total # = 600
Looks good!
![Image](https://i.imgur.com/YCxbQ7s.png)
Stuart Kovinsky | Kaplan GMAT Faculty | Toronto
Kaplan Exclusive: The Official Test Day Experience | Ready to Take a Free Practice Test? | Kaplan/Beat the GMAT Member Discount
BTG100 for $100 off a full course
-
- Junior | Next Rank: 30 Posts
- Posts: 16
- Joined: Tue Feb 05, 2008 10:47 am
- Thanked: 3 times
- Stuart@KaplanGMAT
- GMAT Instructor
- Posts: 3225
- Joined: Tue Jan 08, 2008 2:40 pm
- Location: Toronto
- Thanked: 1710 times
- Followed by:614 members
- GMAT Score:800
Yah, seems like (2) should be sufficient alone.davidforsberg wrote:so you're saying that the correct answer is B instead of C???
![Image](https://i.imgur.com/YCxbQ7s.png)
Stuart Kovinsky | Kaplan GMAT Faculty | Toronto
Kaplan Exclusive: The Official Test Day Experience | Ready to Take a Free Practice Test? | Kaplan/Beat the GMAT Member Discount
BTG100 for $100 off a full course