Is Root of x a prime number?
(i) Abs (3x-7)= 2x+2
(ii) x to the power 2= 9x
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Prime Number
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Rahul@gurome
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Statement 1: |3x - 7| = (2x + 2)Viper83 wrote:Is Root of x a prime number?
(i) Abs (3x-7)= 2x+2
(ii) x to the power 2= 9x
Absolute value gives rise to two situations,
- (1) For 3x > 7, (3x - 7) = (2x + 2) => x = 9 => √x = 3 -> Prime
or
(2) For 3x < 7, (7 - 3x) = (2x + 2) => x = 1 => √x = 1 -> Not Prime
Statement 2: x² = 9x
=> x² - 9x = 0 => x(x - 9) = 0 => x = 0 or 9
Not sufficient.
1 & 2 Together: x = 9 => √x = 3 -> Prime
Sufficient.
The correct answer is C.
Rahul Lakhani
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Hi Rahul
thanks very much for your reply and explanation. In fact I solved the questions exactly like that.
My concern with this question is the following: why is the square root of 9 equal to ONLY 3. The square root of 9 should be 3 and -3. Furthermore, -3 is not a prime number.
What am I missing here?
Thanks very much!
thanks very much for your reply and explanation. In fact I solved the questions exactly like that.
My concern with this question is the following: why is the square root of 9 equal to ONLY 3. The square root of 9 should be 3 and -3. Furthermore, -3 is not a prime number.
What am I missing here?
Thanks very much!
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Rahul@gurome
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When we are dealing with square root(s), it is always the positive one.Viper83 wrote:My concern with this question is the following: why is the square root of 9 equal to ONLY 3. The square root of 9 should be 3 and -3. Furthermore, -3 is not a prime number.
What am I missing here?
By definition √(x²) = |x|.
This means, if x² = 9, and we are asked to find the value of x, the answer is -3 and 3. But if are asked to find the value of √(x²), the answer is only 3.
Rahul Lakhani
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Viper83 wrote:
Is Root of x a prime number?
(i) Abs (3x-7)= 2x+2
(ii) x to the power 2= 9x
Statement 1: |3x - 7| = (2x + 2)
Absolute value gives rise to two situations,
(1) For 3x > 7, (3x - 7) = (2x + 2) => x = 9 => √x = 3 -> Prime
or
(2) For 3x < 7, (7 - 3x) = (2x + 2) => x = 1 => √x = 1 -> Not Prime
Not sufficient.
Statement 2: x² = 9x
=> x² - 9x = 0 => x(x - 9) = 0 => x = 0 or 9
Not sufficient.
1 & 2 Together: x = 9 => √x = 3 -> Prime
Sufficient.
I have a question for Rahul, can't we ignore x = 0 in the second case because root(0) is not considered? By this, the ans. would be B.
Actually this brings me to another question as to how is root(0) treated?
Is Root of x a prime number?
(i) Abs (3x-7)= 2x+2
(ii) x to the power 2= 9x
Statement 1: |3x - 7| = (2x + 2)
Absolute value gives rise to two situations,
(1) For 3x > 7, (3x - 7) = (2x + 2) => x = 9 => √x = 3 -> Prime
or
(2) For 3x < 7, (7 - 3x) = (2x + 2) => x = 1 => √x = 1 -> Not Prime
Not sufficient.
Statement 2: x² = 9x
=> x² - 9x = 0 => x(x - 9) = 0 => x = 0 or 9
Not sufficient.
1 & 2 Together: x = 9 => √x = 3 -> Prime
Sufficient.
I have a question for Rahul, can't we ignore x = 0 in the second case because root(0) is not considered? By this, the ans. would be B.
Actually this brings me to another question as to how is root(0) treated?
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Rahul@gurome
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Our target is to identify the correct option, not to force an option to be the correct one. If there is a logic to ignore x = 0, we can certainly do that. But as there is none, we can't ignore it. And root of zero is zero only, which is not a prime number.gdk800 wrote:I have a question for Rahul, can't we ignore x = 0 in the second case because root(0) is not considered? By this, the ans. would be B.
Actually this brings me to another question as to how is root(0) treated?
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
