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Junior | Next Rank: 30 Posts
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by torontogmat.com » Thu Feb 28, 2008 7:43 am
Essentially you are being asked how many 3's you have in 9!.

In order for 9! / 3^k to be an integer, you must have at least k 3's in the numerator.

9! has four 3's: the 9 accounts for two of them, and the 6 and 3 for one each.
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by sampleresume » Wed Apr 16, 2008 6:51 am
I will go with 4 too.
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