[GMAT math practice question]
A factory has two machines. Machine X can produce 200 pins per hour and machine Y can produce 500 pins per hour. At least one machine is in operation throughout the 8-hour work day. The factory must produce 5,000 pins every day. What is the least possible number of hours that machines X and Y must work together on each day?
A. 4
B. 5
C. 6
D. 7
E. 8
A factory has two machines. Machine X can produce 200 pins p
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In order to minimize the number of hours that the two machines work together, the more efficient machine Y should work for the entire day.
Thus, Y works for 8 hours and produces 8 * 500 = 4,000 pins.
There are 1,000 pins remaining for machine X to produce. This takes 1,000/200 = 5 hours.
Therefore, B is the answer.
Answer: B
In order to minimize the number of hours that the two machines work together, the more efficient machine Y should work for the entire day.
Thus, Y works for 8 hours and produces 8 * 500 = 4,000 pins.
There are 1,000 pins remaining for machine X to produce. This takes 1,000/200 = 5 hours.
Therefore, B is the answer.
Answer: B
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