If the sum of 3 consecutive integers is 54, then what is the product of the smallest and largest of these integers?
a) 280
b) 292
c) 312
d) 320
e) 323
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If the sum of 3 consecutive integers is 54, then what is the
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BTGmoderatorDC
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Average of the 3 consecutive integers = sum/quantity = 54/3 = 18.BTGmoderatorDC wrote:If the sum of 3 consecutive integers is 54, then what is the product of the smallest and largest of these integers?
a) 280
b) 292
c) 312
d) 320
e) 323
For any set of consecutive integers, average = median.
Thus, the median of the 3 integers = 18, implying that the 3 integers are 17, 18, and 19.
Product of the smallest and largest = 17*19 = integer with a units digit of 3.
The correct answer is E.
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Since the sum of 3 consecutive integers is 54, the middle integer must be the average, which is 54/3 = 18. So the smallest integer must be 17 and the largest must be 19. So the product is 17 x 19 = 323.BTGmoderatorDC wrote:If the sum of 3 consecutive integers is 54, then what is the product of the smallest and largest of these integers?
a) 280
b) 292
c) 312
d) 320
e) 323
Answer: E
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