Q35:
In Patton City, days are categorized as having heavy rainfall (more than two inches),
moderate rainfall (more than one inch, but no more than two inches), light rainfall (at
least a trace, but no more than one inch), or no rainfall. In 1990, there were fewer days
with light rainfall than in 1910 and fewer with moderate rainfall, yet total rainfall for the
year was 20 percent higher in 1990 than in 1910.
If the statements above are true, then it is also possible that in Patton City
A. the number of days with heavy rainfall was lower in 1990 than in 1910
B. the number of days with some rainfall, but no more than two inches, was the same
in 1990 as in 1910
C. the number of days with some rainfall, but no more than two inches, was higher in
1990 than in 1910
D. the total number of inches of rain that fell on days with moderate rainfall in 1990
was more than twice what it had been in 1910
E. the average amount of rainfall per month was lower in 1990 than in 1910
will give the OA later on...pl. explain ur ans...thanx;
SET 29 V Q 35: is any of the choices correct?
This topic has expert replies
-
- Master | Next Rank: 500 Posts
- Posts: 460
- Joined: Sun Mar 25, 2007 7:42 am
- Thanked: 27 times
My undertanding here is that if total rainfall in 1910 was x then in 1990 it was 1.2x with fewer days of moderate & light rainfall as compared to that in 1910. (howver total rainfall would utilmately depend upon the total inches of rainfall rather than days)
so this is possible only if
a) the total haeavy rainfall in inches in 1990 was more than 1910
b) total moderate or light rf in inches in 1990 was more than 1910
now the Q asks
If the statements above are true, then it is also possible that in Patton City
so D is the choice which logically supports the arguement, as it says that total amt of moderate rainfall was more in 1990 than 1910 which may account for the 20% inc
what is the OA
so this is possible only if
a) the total haeavy rainfall in inches in 1990 was more than 1910
b) total moderate or light rf in inches in 1990 was more than 1910
now the Q asks
If the statements above are true, then it is also possible that in Patton City
so D is the choice which logically supports the arguement, as it says that total amt of moderate rainfall was more in 1990 than 1910 which may account for the 20% inc
what is the OA
Regards
Samir
Samir
-
- Senior | Next Rank: 100 Posts
- Posts: 36
- Joined: Sat Jul 21, 2007 10:55 am
- Location: India
- Thanked: 1 times
the OA is not D...surprised? let's 've some more discussion...ur logic is fine...but why total inches of rf more than twice?...sud such exact conclusion can be drawn on the basis of the above info?
Hi friends ! Just started GMAT prep. Hope to share thoughts, experience, joy and agony of GMAT prep journey.
Regards; neeraj
Regards; neeraj
-
- Master | Next Rank: 500 Posts
- Posts: 460
- Joined: Sun Mar 25, 2007 7:42 am
- Thanked: 27 times
Hi Neeraj,
U are right but the Q also asks abt a possiility & not an fact so thats why D seems possible to me.
U are right but the Q also asks abt a possiility & not an fact so thats why D seems possible to me.
Regards
Samir
Samir
here is my analysis:
A: Negate A coz the heavy rf stats are not discussed b/w 1990 and 1910
B: Negate B coz the no. of days with some rf (that includes moderate and light) is fewer is 1990 than in 1910...cannot be same
C: Negate C coz the no. of days with some rf (that includes moderate and light) is fewer is 1990 than in 1910...cannot be same..explanation same as B
D: Negate D coz the it is not sure that the moderate rainfall in 1990 is twice the moderate rainfall in 1910..
that leaves the answer E..logically it is also true...the no. of days of rainfall in 1990 is fewer than no. of days in 1910 and the amount of rainfall in 1990 is more than amount of rainfall in 1910..mathematically if u take the avg (no. of days/ total rainfall)...the avg for 1990 comes out to be less...I guess..
OA please?
A: Negate A coz the heavy rf stats are not discussed b/w 1990 and 1910
B: Negate B coz the no. of days with some rf (that includes moderate and light) is fewer is 1990 than in 1910...cannot be same
C: Negate C coz the no. of days with some rf (that includes moderate and light) is fewer is 1990 than in 1910...cannot be same..explanation same as B
D: Negate D coz the it is not sure that the moderate rainfall in 1990 is twice the moderate rainfall in 1910..
that leaves the answer E..logically it is also true...the no. of days of rainfall in 1990 is fewer than no. of days in 1910 and the amount of rainfall in 1990 is more than amount of rainfall in 1910..mathematically if u take the avg (no. of days/ total rainfall)...the avg for 1990 comes out to be less...I guess..
OA please?
-
- Master | Next Rank: 500 Posts
- Posts: 195
- Joined: Sun Oct 21, 2007 4:33 am
- Thanked: 10 times
IMO - A
Heres my (twisted!) analysis...
D - Not possible, because moderate rainfall on any day can never be twice of another day (Min possible is 1.1, Max possible is 2)
E - Not possible. Avg. rainfall per month = Total rainfall in year/12. Since 12 is constant, it only depends on total rainfall which we know is more for 1990 than 1910
B - Not true because
1990L less than 1910L
1990M less than 1910M
so, 1990(L+M) less than 1910(L+M).
Using the same logic for B, we can rule out C too.
So that leaves A
Heres my (twisted!) analysis...
D - Not possible, because moderate rainfall on any day can never be twice of another day (Min possible is 1.1, Max possible is 2)
E - Not possible. Avg. rainfall per month = Total rainfall in year/12. Since 12 is constant, it only depends on total rainfall which we know is more for 1990 than 1910
B - Not true because
1990L less than 1910L
1990M less than 1910M
so, 1990(L+M) less than 1910(L+M).
Using the same logic for B, we can rule out C too.
So that leaves A
-
- Junior | Next Rank: 30 Posts
- Posts: 19
- Joined: Thu Dec 13, 2007 6:45 am
- Thanked: 1 times
IMO A
eliminate E because avg=total/365 therefore not possible.
eliminate B and C because mentioned directly in the question.
eliminate D because moderate- 1 to 2 inches of rain. therefore there is no way in which the statement can be true.
eliminate E because avg=total/365 therefore not possible.
eliminate B and C because mentioned directly in the question.
eliminate D because moderate- 1 to 2 inches of rain. therefore there is no way in which the statement can be true.
Abhishek sunku
-
- Legendary Member
- Posts: 1578
- Joined: Sun Dec 28, 2008 1:49 am
- Thanked: 82 times
- Followed by:9 members
- GMAT Score:720
Isn't A an opposite answer? TestLuv can you explain, I am hacing C as possible answer. Here is my choice:
H: >2 1<M<2 trace<L<1 N
1910 1990
H
M more less
L more less
N
Total: Less More 20%
Opposite answer: A
Irrelevant: No info about average per month rainfall so E out, similarly D as total number of inches per day can not be determined....
Out of B and C: same is not a must, so C wins as it is possible that L+N is more in 90's.
H: >2 1<M<2 trace<L<1 N
1910 1990
H
M more less
L more less
N
Total: Less More 20%
Opposite answer: A
Irrelevant: No info about average per month rainfall so E out, similarly D as total number of inches per day can not be determined....
Out of B and C: same is not a must, so C wins as it is possible that L+N is more in 90's.
Charged up again to beat the beast
-
- GMAT Instructor
- Posts: 1302
- Joined: Mon Oct 19, 2009 2:13 pm
- Location: Toronto
- Thanked: 539 times
- Followed by:164 members
- GMAT Score:800
The correct answer is definitely choice A. I discussed this problem in great detail here: https://www.beatthegmat.com/rainfall-pro ... 45-15.html (I posted on both pages 2, and 3 of the thread).maihuna wrote:Isn't A an opposite answer? TestLuv can you explain, I am hacing C as possible answer. Here is my choice:
H: >2 1<M<2 trace<L<1 N
1910 1990
H
M more less
L more less
N
Total: Less More 20%
Opposite answer: A
Irrelevant: No info about average per month rainfall so E out, similarly D as total number of inches per day can not be determined....
Out of B and C: same is not a must, so C wins as it is possible that L+N is more in 90's.
Kaplan Teacher in Toronto