A certain 4-liter solution of vinegar and water consists of x liters of vinegar and y liters of water. How many liters of vinegar does the solution contain?
(1) x/4 = 3/8
(2) y/4 = 5/8
the answer is D, but can anyone plz help me solve it using equations ....... a complete answer... thank you...
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vinegar and water
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Approach - 1) From (1), x xan be found.leonswati wrote:A certain 4-liter solution of vinegar and water consists of x liters of vinegar and y liters of water. How many liters of vinegar does the solution contain?
(1) x/4 = 3/8
(2) y/4 = 5/8
the answer is D, but can anyone plz help me solve it using equations ....... a complete answer... thank you...
2) From (2), y can be found, which when subtracted from total volume of solution gives the value of x.
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shankar.ashwin
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Given x + y = 4
1) gives you x -> 3/2 (sufficient)
2) gives you y -> 5/2 (and) x = 4 - 5/2 = 3/2 (sufficient)
1) gives you x -> 3/2 (sufficient)
2) gives you y -> 5/2 (and) x = 4 - 5/2 = 3/2 (sufficient)
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neelgandham
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The question can be rephrased to,
If x+y =4, then x = ?
We get the value of x by simplifying. Hence, sufficient
Option D
If x+y =4, then x = ?
(1) x/4 = 3/8
We get the value of x by simplifying. Hence, sufficient
y = A fraction and x+y =4 ; x = 4- A fraction. Hence, sufficient(2) y/4 = 5/8
Option D
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Hi!leonswati wrote:A certain 4-liter solution of vinegar and water consists of x liters of vinegar and y liters of water. How many liters of vinegar does the solution contain?
(1) x/4 = 3/8
(2) y/4 = 5/8
the answer is D, but can anyone plz help me solve it using equations ....... a complete answer... thank you...
This question is a great illustration of the most powerful rule to remember for data sufficiency: number of equations vs number of unknowns.
Here's the "official" wording of the rule:
Put more simply, if you have the same number of linear equations as you have variables, you can answer any question about the system.To solve a system with n variables, one requires n distinct, linear, equations.
Applying the rule to your question:
Q: gives you 1 equation with 2 variables. We're missing 1 more equation.
(1) gives us another linear equation, no new variables: sufficient.
(2) gives us another linear equation, no new variables: sufficient.
Choose (D)!
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