For every positive even integer n, the function h(n) equals the product of all even integers from 2 to n, inclusive. If P is the smallest prime factor of h(100)+1, then P is...
1) Between 2 and 10
2) Between 10 and 20
3) Between 20 and 30
4) Between 30 and 40
PS
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h(100) = 2* 4* 6* ..... *98*100
=> 2*(2*2)*(2*3)....*(2*49)*(2*50)
=> (2^50)(1*2*3....*49*50)
Means - all integers from 1 to 50 are factors of h(100). So, none of them will be factor of h(100)+1
So, smallest prime factor of h(100)+1 will be greater than 50
I think you are missing one option from ur answers choices....
=> 2*(2*2)*(2*3)....*(2*49)*(2*50)
=> (2^50)(1*2*3....*49*50)
Means - all integers from 1 to 50 are factors of h(100). So, none of them will be factor of h(100)+1
So, smallest prime factor of h(100)+1 will be greater than 50
I think you are missing one option from ur answers choices....
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- Master | Next Rank: 500 Posts
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