If p is an integer, what is the value of p?
(1) (|p|!)^p = |p|!
(2) p^p = p^2
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Value of p
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karthikpandian19
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rijul007
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(1) (|p|!)^p = |p|!karthikpandian19 wrote:If p is an integer, what is the value of p?
(1) (|p|!)^p = |p|!
(2) p^p = p^2
this is true for p = 1 or -1
Insufficient
(2) p^p = p^2
p^p = p^2
This is true for p = 1 or 2
Combining two statements
p = 1
Option C
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neelgandham
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An addition to Rijul's solution, The value of p can also be '0' from statement 1rijul007 wrote:(1) (|p|!)^p = |p|!karthikpandian19 wrote:If p is an integer, what is the value of p?
(1) (|p|!)^p = |p|!
(2) p^p = p^2
this is true for p = 1 or -1
Insufficient
(|0|!)^0 = |0|!
1^0 = 1
1=1
Anil Gandham
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santhoshsram
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Just curious. Trying to plug 0 in (2), we get 0^0 on the LHS. Is 0^0 indeterminate or 1 on GMAT?neelgandham wrote:An addition to Rijul's solution, The value of p can also be '0' from statement 1rijul007 wrote:(1) (|p|!)^p = |p|!karthikpandian19 wrote:If p is an integer, what is the value of p?
(1) (|p|!)^p = |p|!
(2) p^p = p^2
this is true for p = 1 or -1
Insufficient
(|0|!)^0 = |0|!
1^0 = 1
1=1
-- Santhosh S
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karthikpandian19
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If it is takes ZERO then there will be 2 solutions and the answer shld be E????
Is that right?
Is that right?
neelgandham wrote:An addition to Rijul's solution, The value of p can also be '0' from statement 1rijul007 wrote:(1) (|p|!)^p = |p|!karthikpandian19 wrote:If p is an integer, what is the value of p?
(1) (|p|!)^p = |p|!
(2) p^p = p^2
this is true for p = 1 or -1
Insufficient
(|0|!)^0 = |0|!
1^0 = 1
1=1
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rijul007
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st(1) would give p= -1, 0 or 1karthikpandian19 wrote:If it is takes ZERO then there will be 2 solutions and the answer shld be E????
Is that right?neelgandham wrote:An addition to Rijul's solution, The value of p can also be '0' from statement 1rijul007 wrote:(1) (|p|!)^p = |p|!karthikpandian19 wrote:If p is an integer, what is the value of p?
(1) (|p|!)^p = |p|!
(2) p^p = p^2
this is true for p = 1 or -1
Insufficient
(|0|!)^0 = |0|!
1^0 = 1
1=1
st(2) would give p = 1 or 2
After Combining the two statements
we get p = 1
So option C should be the ans
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karthikpandian19
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Got it
i checked OA is C
i checked OA is C
rijul007 wrote:st(1) would give p= -1, 0 or 1karthikpandian19 wrote:If it is takes ZERO then there will be 2 solutions and the answer shld be E????
Is that right?neelgandham wrote:An addition to Rijul's solution, The value of p can also be '0' from statement 1rijul007 wrote:(1) (|p|!)^p = |p|!karthikpandian19 wrote:If p is an integer, what is the value of p?
(1) (|p|!)^p = |p|!
(2) p^p = p^2
this is true for p = 1 or -1
Insufficient
(|0|!)^0 = |0|!
1^0 = 1
1=1
st(2) would give p = 1 or 2
After Combining the two statements
we get p = 1
So option C should be the ans
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Yes the correct answer is C...
Statement 1: The possible values could be {-1, 0, 1}
Statement 2: The possible values are {1 , 2}
Using Both statements:
The correct answer comes down to C...
Statement 1: The possible values could be {-1, 0, 1}
Statement 2: The possible values are {1 , 2}
Using Both statements:
The correct answer comes down to C...
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Brent@GMATPrepNow
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Hi santhoshsram,santhoshsram wrote: Just curious. Trying to plug 0 in (2), we get 0^0 on the LHS. Is 0^0 indeterminate or 1 on GMAT?
That's a difficult (even contentious) question to answer.
Some will say that 0^0 = 1, and that's fine. I think it's safe to say that you don't need to worry about it. The GMAT will not test you on the value of 0^0.
For more, please see https://www.beatthegmat.com/what-is-the- ... 27026.html
Cheers,
Brent
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