alltimeacheiver wrote:Any decimal that has only a finite number of nonzero digits is a terminating decimal. For example, 36, 0.72, and 3.005 are terminating decimals.
If a, b, c, d and e are non-negative integers and p = (2^a) (3^b) and q = (2^c) (3^d) (5^e), is
p/q a terminating decimal?

(1) a > c

(2) b > d

We have to find if p/q = (2^a)(3^b)/(2^c)(3^d)(5^e) = 2^(a-c)*3^(b-d)/5^e is a terminating decimal.

(1) a > c is NOT SUFFICIENT to answer the above question, as we don't know b and d.

(2) b > d is SUFFICIENT.
It can be noticed that 2^(a-c) and 5^e will always be a terminating decimal. Any power of 2 and 5 gives a terminating decimal.
The only info we needed was about the power of 3, and since b > d, so b - d will be positive.
So, p/q will be a terminating decimal
So, (2) is SUFFICIENT.

The correct answer is B.