Q14:
A three-digit code for certain logs uses the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 according to the
following constraints. The first digit cannot be 0 or 1, the second digit must be 0 or 1, and the
second and third digits cannot both be 0 in the same code. How many different codes are
possible?
A. 144
B. 152
C. 160
D. 168
E. 176
Answer:
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please tell me the OA
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vivek.kapoor83
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vivek.kapoor83
- Legendary Member
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- Joined: Mon Aug 04, 2008 1:56 am
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For 1st postion u can have 8 digits.
for 2nd if u consider 0 then 9 combinations( as 0 at 3rd Place is not allowed)
So, 8*1*9 =72 Combinations possible
If u consider 1 at 2nd place.
1st place = 8
2nd place =1
3rd place = 10
8*1*10 =80
80+72 = 152
OA Pls
for 2nd if u consider 0 then 9 combinations( as 0 at 3rd Place is not allowed)
So, 8*1*9 =72 Combinations possible
If u consider 1 at 2nd place.
1st place = 8
2nd place =1
3rd place = 10
8*1*10 =80
80+72 = 152
OA Pls
