Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Please provide a detailed solution for this problem

Expert replies
by Architj » Wed May 06, 2015 5:36 am
In 1985 a company sold a brand of shoes to retailers for a fixed price per pair. In 1986 the number of pairs of the shoes that the company sold to retailers decreased by 20 percent, while the price per pair increased by 20 percent. If the company’s revenue from the sale of the shoes in 1986 was $3.0 million, what was the approximate revenue from the sale of the shoes in 1985?

(A) $2.4 million
(B) $2.9 million
(C) $3.0 million
(D) $3.1 million
(E) $3.6 million
Join the discussion
Source: — Problem Solving |

by coolhabhi » Wed May 06, 2015 5:53 am
[quote="Architj"]In 1985 a company sold a brand of shoes to retailers for a fixed price per pair. In 1986 the number of pairs of the shoes that the company sold to retailers decreased by 20 percent, while the price per pair increased by 20 percent. If the company’s revenue from the sale of the shoes in 1986 was $3.0 million, what was the approximate revenue from the sale of the shoes in 1985?

(A) $2.4 million
(B) $2.9 million
(C) $3.0 million
(D) $3.1 million
(E) $3.6 million[/quote]

Suppose in the year 1985 the number of pairs of shoes sold = 100 &
the price per pair = 100 => the Total Revenue = 100x100 = 10000

Then in the year 1986 the number of pairs of shoes sold = 80 &
the price per pair = 120 => the Total Revenue = 80x120 = 9600

It is given the company’s revenue from the sale of the shoes in 1986 was $3.0 million
So if 9600 equals $3.0 million
then 10000 equals = (10000/9600)x $3.0 million = 1.042 x $3.0 million = 3.125 million

Answer [spoiler]D[/spoiler]
Join the discussion

by GMATGuruNY » Wed May 06, 2015 5:54 am
Architj wrote:In 1985 a company sold a brand of shoes to retailers for a fixed price per pair. In 1986 the number of pairs of the shoes that the company sold to retailers decreased by 20 percent, while the price per pair increased by 20 percent. If the company’s revenue from the sale of the shoes in 1986 was $3.0 million, what was the approximate revenue from the sale of the shoes in 1985?

(A) $2.4 million
(B) $2.9 million
(C) $3.0 million
(D) $3.1 million
(E) $3.6 million
To determine the revenue ratio for 1986 to 1985, TEST AN EASY CASE.

1985:
Let the number of pairs sold = 10.
Let the price per pair = 10.
Total revenue = (number of pairs)(price per pair) = 10*10 = 100.

1986:
Since 20% fewer pairs are sold, the number of pairs = 10 - 20% of 10 = 10-2 = 8.
Since the price per pair increases by 20%, the price per pair = 10 + 20% of 10 = 10+2 = 12.
Total revenue = (number of pairs)(price per pair) = 8*12 = 96.

Resulting ratio:
(revenue in 1986)/(revenue in 1985) = 96/100 = 24/25.

Since the actual revenue in 1986 = 3 million, set up the following proportion:
24/25 = 3/x
24x = 75
x = 3.125.

The correct answer is D.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by j_shreyans » Wed May 06, 2015 9:07 am
Hi ,

Can you please advise that why did you do by taking ratio? Is there any other method to solve this?

Resulting ratio:
(revenue in 1986)/(revenue in 1985) = 96/100 = 24/25.

Since the actual revenue in 1986 = 3 million, set up the following proportion:
24/25 = 3/x
24x = 75
x = 3.125.
Join the discussion

by [email protected] » Wed May 06, 2015 9:15 am
Hi All,

This question can be dealt with in a number of different ways. Here's an algebraic approach:

N = number of pairs of shoes
P = price per pair

1985 = (N)(P)

We're then told that in 1986 the NUMBER of pairs DECREASED by 20% and the PRICE per pair INCREASED by 20%....

1986 = (.8N)(1.2P) = .96(N)(P)

We're then told that revenue in 1986 was $3.0 million....

.96NP = 3,000,000

And we're asked for the revenue in 1985, which means that we want the value of (N)(P)...

NP = 3,000,000/.96

From this, we can see the NP is a little greater than 3,000,000. There's only one answer that fits...

Final Answer: D

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion

by Scott@TargetTestPrep » Wed Jan 03, 2018 4:05 pm
Architj wrote:In 1985 a company sold a brand of shoes to retailers for a fixed price per pair. In 1986 the number of pairs of the shoes that the company sold to retailers decreased by 20 percent, while the price per pair increased by 20 percent. If the company’s revenue from the sale of the shoes in 1986 was $3.0 million, what was the approximate revenue from the sale of the shoes in 1985?

(A) $2.4 million
(B) $2.9 million
(C) $3.0 million
(D) $3.1 million
(E) $3.6 million
We can let the number of pairs of shoes sold in 1985 = n and the price per pair = p.

Thus, the revenue in 1985 is np and we can create the following equation for the revenue in 1986:

(0.8n)(1.2p) = 3,000,000

0.96np = 3,000,000

np = 3,125,000, which is roughly 3.1 million.

Answer: D

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage
Join the discussion