BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Please help to solve this Tough DS question.

Expert replies
by GaneshMalkar » Mon May 27, 2013 5:53 am
In the xy coordinate plane, line L and line K intersect at the point (4,3). Is the product of their slopes negative?
(1) The product of the x-intersects of lines L and K is positive.
(2) The product of the y-intersects of lines L and K is negative.


Source - Tough 700 Questionnaire.

OA - C


I searched this question on this forum and found that

L = a1x + b1
K = a2x + b2

Slope L : -b1/a1
Slope K : -b2/a2

But the slope form of the equation is y = mx + c, so the above equation should have slope as a1 only and not -b1/a1


If the equation is in standard form Ax + By + C = 0 then y = -A/Bx - C/A
then the slope is -A/b and y-intercept = - C/A


So L = a1x + b1 is in which form?
If you cant explain it simply you dont understand it well enough!!!
- Genius
Join the discussion
Source: — Data Sufficiency |

by sanjayism » Mon May 27, 2013 6:34 am
Lets us write the equation of line in intercept form.

equation of line L is x/a + y/b = 1
equation of line K is x/c + y/d = 1


slope of line L is =-(b/a)
slope of line K is =-(d/c)

product of slopes = -(b/a) * -(d/c)= bd/ac

we have dertermine whether bd/ac is negative or not.


statment1 = a*c >0

from above statment it is not possible to say that bd/ac is nagative. it will depends on bd, if bd is positive then bd/ac is positive and vice versa.

so S1 is not sufficint to decide the answer.

similarlly , SM2 is not sufficient to answer the question clearly. if bd is negative then it is not possible to say that bd/ac is nagative. it will depends on ac, if ac is positive then bd/ac is positive and vice versa.

if both statment consider jointly then it can be answered clearly.

SM1 ac>0
SM2 bd<0

so product of slope i.e. bd/ac <0

so answer is c
kumar sanjay
Join the discussion

by GMATGuruNY » Mon May 27, 2013 7:21 pm
In the XY-coordinate plane, line L and line K intersect at the point (4, 3). Is the product of their slopes negative?

(1) The product of the x-intercepts of line L and K is positive.
(2) The product of the y-intercepts of line L and k is negative.
Don't solve. Draw.

Statement 1: The product of the x-intercepts of line L and K is positive.
K has a negative x-intercept, L has a negative x-intercept, the product of the slopes is positive:
Image

K has a positive x-intercept, L has a positive x-intercept, the product of the slopes is negative:
Image
INSUFFICIENT.

Statement 2: The product of the y-intercepts of line L and k is negative.
K has a negative y-intercept, L has a positive y-intercept, the product of the slopes is negative:
Image

K has a negative y-intercept, L has a positive y-intercept, the product of the slopes is positive:
Image
INSUFFICIENT.

Statements 1 and 2 combined:
Statement 1 requires that both x-intercepts be negative or that both x-intercepts be positive (so that their product is positive).
If both x-intercepts are negative, then both y-intercepts must be positive, which does not satisfy statement 2:
Image

Thus, both x-intercepts must be positive.
Statement 2 requires that one of the y-intercepts be positive, the other negative.
A positive x-intercept and a positive y-intercept yields a negative slope.
A positive x-intercept and a negative y-intercept yields a positive slope.
See below:
Image
Thus, the product of the slopes must be negative.
SUFFICIENT.

The correct answer is C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by GaneshMalkar » Tue May 28, 2013 8:56 am
Thank you very much Mitch.
Can you please confirm my below understanding if it is right or wrong?

1. If a line in a plane is directed in a north-east direction it will have a positive slope.
2. if a line in a plane is directed in a south-east direction it will have a negative slope.
3. If a line is parallel to y-axis the slope is not defined.
4. If a line is parallel to x-axis the slope is zero.


So in this way, we have evaluated the four cases in the statement 1 and statement 2 will not poise any problem correct?
If you cant explain it simply you dont understand it well enough!!!
- Genius
Join the discussion