This question has stumped me. Does anyone have a good strategy for this?
On a team, the number of males is 3 fewer than twice the number of females. If one male were replaced by a female, there would be an equal number of males and females on the team. How many members are on the team?
a 14
b 12
c 10
d 9
e 7
Thanks!
Please explain 600700 level questionalgebraic translation
This topic has expert replies
The number of males is 3 fewer than twice the number of females.
M = 2F3
If one male were replaced by a female, there would be an equal number of males and females on the team.
M1 = F+1
Solve these two equation and you will get F= 5 and M= 7
How many members are on the team?
12
M = 2F3
If one male were replaced by a female, there would be an equal number of males and females on the team.
M1 = F+1
Solve these two equation and you will get F= 5 and M= 7
How many members are on the team?
12

 Master  Next Rank: 500 Posts
 Posts: 136
 Joined: 28 Sep 2008
 Location: fssf
 Thanked: 17 times
IMO Brtaha2412 wrote:This question has stumped me. Does anyone have a good strategy for this?
On a team, the number of males is 3 fewer than twice the number of females. If one male were replaced by a female, there would be an equal number of males and females on the team. How many members are on the team?
a 14
b 12
c 10
d 9
e 7
Thanks!
Male = M
Female = F
the number of males is 3 fewer than twice the number of females M=2F3(1)
If one male were replaced by a female, there would be an equal number of males and females on the teamM1=F+1(2)
Simplifying (2).. M=F+2
Substituting the value of M in (1) We get F=5.
Therefore M=7
M+F =12
HTH!!
Aiming High