A jar contains 8 red marbles and y white marbles. If Joan takes 2 random marbles from the jar, is it more likely that she will have 2 red marbles than that she will have one marble of each color?
(1) y ≤ 8
(2) y ≥ 4
Pick marbles please
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- sl750
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Statement 1
Let's assume y=8
P(Two Red marbles) = 8/16*7/15
P(One Red and One white marble) = 2(8/16*8/15)
In this case P(Two red marbles) < P(One Red and One White marble)
When y =1
P(Two red marbles) = 8/9*7/8
P(One Red and One white marble) = 2(8/9*1/8)
In this case P(Two red marbles) > P(One Red and One White marble). Insufficient
Statement 2
Let's assume y=4
P(Two Red marbles) = 8/12*7/11
P(One Red and One White marble) = 2(8/12*4/11)
In this case P(Two Red marbles) < P(One Red and One White marble)
We have already seen a case where y=8. i.e, as y increases we are certain that we will have only
one answer. Sufficient
Let's assume y=8
P(Two Red marbles) = 8/16*7/15
P(One Red and One white marble) = 2(8/16*8/15)
In this case P(Two red marbles) < P(One Red and One White marble)
When y =1
P(Two red marbles) = 8/9*7/8
P(One Red and One white marble) = 2(8/9*1/8)
In this case P(Two red marbles) > P(One Red and One White marble). Insufficient
Statement 2
Let's assume y=4
P(Two Red marbles) = 8/12*7/11
P(One Red and One White marble) = 2(8/12*4/11)
In this case P(Two Red marbles) < P(One Red and One White marble)
We have already seen a case where y=8. i.e, as y increases we are certain that we will have only
one answer. Sufficient
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Hi sl750,
Why have you taken P(One Red and One white marble) = 2(8/16*8/15) . Why the multiple of 2? Whichever way red and white marbles are picked, the likelihood of the event to occur will not change
Why have you taken P(One Red and One white marble) = 2(8/16*8/15) . Why the multiple of 2? Whichever way red and white marbles are picked, the likelihood of the event to occur will not change