A certain company assigns employees to offices in such a way that some of the offices can be empty and more than one employee can be assigned to an office. In how many ways can the company assign 3 employees to 2 different offices?
A. 5
B. 6
C. 7
D. 8
E. 9
friends please explain , I am getting only 4 ways but the OA is A
permutations and combination
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- kamu
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Hi,
there are two offices and three employees.
so three employees can be assigned to one room(say A) in 1 way
in the same way three employees can be assigned to one room(say B) in 1 way
and
two employees can be put in one room(A) and one employee in another room(B) in 3C1*2C2 ways=3
and
two employees can be put in one room(B) and one employee in another room(A) in 3C1*2C2 ways=3
total is 1+1+3+3=8 ways.
there are two offices and three employees.
so three employees can be assigned to one room(say A) in 1 way
in the same way three employees can be assigned to one room(say B) in 1 way
and
two employees can be put in one room(A) and one employee in another room(B) in 3C1*2C2 ways=3
and
two employees can be put in one room(B) and one employee in another room(A) in 3C1*2C2 ways=3
total is 1+1+3+3=8 ways.