Permutation percentage combination

deltaforce wrote:Hi,
wud app. someone solving this...

Anthony and Michael sit on the six-member board of directors for company X. If the board is to be split up into 2 three-person subcommittees, what percent of all the possible subcommittees that include Michael also include Anthony?

Ans - [spoiler]40%[/spoiler]

the way i approached this problem is

nos of ways to total comm. is 6c3 * 3c3 = 20
nos of ways where bot mike and anthony are on the same team = 4c1 *2c2 = 4

=4/20 * 100 = 20% of all teams

But the answer is something else. what's wrong with my approach?

Thanks

deltaforce wrote:Hi,
wud app. someone solving this...

Anthony and Michael sit on the six-member board of directors for company X. If the board is to be split up into 2 three-person subcommittees, what percent of all the possible subcommittees that include Michael also include Anthony?

Ans - [spoiler]40%[/spoiler]

the way i approached this problem is

nos of ways to total comm. is 6c3 * 3c3 = 20
nos of ways where bot mike and anthony are on the same team = 4c1 *2c2 = 4

=4/20 * 100 = 20% of all teams

But the answer is something else. what's wrong with my approach?

Thanks

deltaforce wrote:Hi,
wud app. someone solving this...

Anthony and Michael sit on the six-member board of directors for company X. If the board is to be split up into 2 three-person subcommittees, what percent of all the possible subcommittees that include Michael also include Anthony?

Ans - [spoiler]40%[/spoiler]

the way i approached this problem is

nos of ways to total comm. is 6c3 * 3c3 = 20
nos of ways where bot mike and anthony are on the same team = 4c1 *2c2 = 4

=4/20 * 100 = 20% of all teams

But the answer is something else. what's wrong with my approach?

Thanks