4 letters are randomly selected from PROPORTION.
a) Number of ways for selecting 3 alike and one different
b) Number of ways for selecting 2 alike and 2 others alike
c) Number of ways for selecting 2 alike and 2 other different
d) Number of ways for selecting all 4 different
Requesting to help me on solving this question.
P.S Answers are not available since I got the questions from a Handout
Permutaiton and Combination -Letter Problem
This topic has expert replies
-
- Junior | Next Rank: 30 Posts
- Posts: 22
- Joined: Sat Apr 19, 2014 5:24 am
- Quasar Chunawala
- Newbie | Next Rank: 10 Posts
- Posts: 7
- Joined: Wed Apr 16, 2014 9:41 pm
- Thanked: 4 times
Given data
The frequency of each of the distinct alphabets in the word PROPORTION are:
P = 2, R = 2, O = 3, T = 1, I = 1, N = 1
Total no. of alphabets with repetitions = 10
Total no. of distinct alphabets = 6
a) No. of ways to select 3 alike = 1
No. of ways to select 1 different from 5 distinct letters = C(5,1) = 5
Total no. of ways = 5 x 1 = 5
b) No. of ways to select 2 alike = 3
Remaining letters are 2.
No. of ways to select the other 2 alike = 2.
Total no. of ways = 3 x 2 = 6
c) No. of ways to select 2 alike = 3
Remaining letters are two.
No. of ways you can select 2 distinct letters from 5
= C(5,2) = 10
Total no. of ways = 3 x 10 = 30
d)No. of ways of selecting all 4 different.
C(6,4) = C(6,2) = 21.
Experts, need your help on this one!
The frequency of each of the distinct alphabets in the word PROPORTION are:
P = 2, R = 2, O = 3, T = 1, I = 1, N = 1
Total no. of alphabets with repetitions = 10
Total no. of distinct alphabets = 6
a) No. of ways to select 3 alike = 1
No. of ways to select 1 different from 5 distinct letters = C(5,1) = 5
Total no. of ways = 5 x 1 = 5
b) No. of ways to select 2 alike = 3
Remaining letters are 2.
No. of ways to select the other 2 alike = 2.
Total no. of ways = 3 x 2 = 6
c) No. of ways to select 2 alike = 3
Remaining letters are two.
No. of ways you can select 2 distinct letters from 5
= C(5,2) = 10
Total no. of ways = 3 x 10 = 30
d)No. of ways of selecting all 4 different.
C(6,4) = C(6,2) = 21.
Experts, need your help on this one!
GMAT/MBA Expert
- Brent@GMATPrepNow
- GMAT Instructor
- Posts: 16207
- Joined: Mon Dec 08, 2008 6:26 pm
- Location: Vancouver, BC
- Thanked: 5254 times
- Followed by:1268 members
- GMAT Score:770
s91arvindh wrote:4 letters are randomly selected from PROPORTION.
a) Number of ways for selecting 3 alike and one different
b) Number of ways for selecting 2 alike and 2 others alike
c) Number of ways for selecting 2 alike and 2 other different
d) Number of ways for selecting all 4 different
Requesting to help me on solving this question.
P.S Answers are not available since I got the questions from a Handout
Please post only one question per thread. Otherwise things can become pretty complicated when there are discussions on multiple questions.
Cheers,
Brent