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Enjoy!

by enniguy » Sat Aug 22, 2009 7:49 am
https://www.manhattangmat.com/forums/the ... -t887.html

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by italian7745 » Sat Aug 22, 2009 7:51 am
This question is basically an application question of indirect proportions...

Let R1 be the rate and A1 and B1 be the concentrations..

R1=K1.A1^2=K2/B1...EQUATION 1)...

Now concentration of B1 is increased by 100% so B2=2B1...

R2=K3.A2^2=K4/B2...EQUATION 2)...

We know that rate is inversely proportional to concentration of B..we have increased the quantity of B ...So the rate shall decrease...which leads to the application of indirect proportion...

To maintain the same rate , R1=R2...

R1/R2 = K1.A1^2/K3.A2^2 = K4/B2/K2/B1...EQUATION 3).

After solving this equation...

A1^2.B2=A2^2.B1

A2^2/A1^2=2

A2/A1=(Square root) 2

A2= 1.414 A1..

So concentration is approx. increased by 40%...
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