Each participant in a certain study was assigned a sequence of 3 different letters from the set {A, B, C, D, E, F, G, H}. If no sequence was assigned to more than one participant and if 36 of the possible sequences were not assigned, what was the number of participants in the study? (Note, for example, that the sequence A, B, C is different from the sequence C, B, A.)
A. 20
B. 92
C. 300
D. 372
E. 476
OA-C
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kaulnikhil
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take permutation since order imp
8p3 = 332
now subtract 32 from this as 32 wernt distributed hence
ans = 332 - 32
= 300
8p3 = 332
now subtract 32 from this as 32 wernt distributed hence
ans = 332 - 32
= 300
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PussInBoots
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mmslf75
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8 * 7 * ^ = 336gmat740 wrote:Each participant in a certain study was assigned a sequence of 3 different letters from the set {A, B, C, D, E, F, G, H}. If no sequence was assigned to more than one participant and if 36 of the possible sequences were not assigned, what was the number of participants in the study? (Note, for example, that the sequence A, B, C is different from the sequence C, B, A.)
A. 20
B. 92
C. 300
D. 372
E. 476
OA-C
336 - 36 = 300 simple!!
Does "" If no sequence was assigned to more than one participant "" mean that each got different sequences ??
If so, then I guess my reasoining is right !!
