If 16 oranges are distributed among 4 children such that each gets at least 3 oranges, the number of ways of distributing them is
A) 30
B) 210
C) 15
D) 35
E) 40
I don't have the OA for this.
Orange
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Following can be the only possible combinations:
(3337), (3346), (3355), (3445) and (4444)
So total number of ways of distributed (3337) among 4 is = 4
Number of ways of distributing (3346) is = 12
Number of ways of distributing (3355) is = 6
Number of ways of distributing (3445) is = 12
Number of ways of distributing (4444) is = 1
So total is 4+12+6+12+1 = 35
D
(3337), (3346), (3355), (3445) and (4444)
So total number of ways of distributed (3337) among 4 is = 4
Number of ways of distributing (3346) is = 12
Number of ways of distributing (3355) is = 6
Number of ways of distributing (3445) is = 12
Number of ways of distributing (4444) is = 1
So total is 4+12+6+12+1 = 35
D
beat_gmat_09 wrote:If 16 oranges are distributed among 4 children such that each gets at least 3 oranges, the number of ways of distributing them is
A) 30
B) 210
C) 15
D) 35
E) 40
I don't have the OA for this.
-
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Even I am getting 35-sachin2411 wrote:Following can be the only possible combinations:
(3337), (3346), (3355), (3445) and (4444)
So total number of ways of distributed (3337) among 4 is = 4
Number of ways of distributing (3346) is = 12
Number of ways of distributing (3355) is = 6
Number of ways of distributing (3445) is = 12
Number of ways of distributing (4444) is = 1
So total is 4+12+6+12+1 = 35
D
Assume that 3 oranges are distributed among 4, total distributed = 3*4 = 12
Left = 16-12 = 4 oranges.
To distribute 4 oranges among 4 children use this relation - C(n+r-1,n-1)
n=r=4
C(4+4-1,4-1) = C(7,3) = 35
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Yes its more concise i guess, but people should know the non negative integral solution of a+b+c+d=4, if you know then you are done.
beat_gmat_09 wrote:Even I am getting 35-sachin2411 wrote:Following can be the only possible combinations:
(3337), (3346), (3355), (3445) and (4444)
So total number of ways of distributed (3337) among 4 is = 4
Number of ways of distributing (3346) is = 12
Number of ways of distributing (3355) is = 6
Number of ways of distributing (3445) is = 12
Number of ways of distributing (4444) is = 1
So total is 4+12+6+12+1 = 35
D
Assume that 3 oranges are distributed among 4, total distributed = 3*4 = 12
Left = 16-12 = 4 oranges.
To distribute 4 oranges among 4 children use this relation - C(n+r-1,n-1)
n=r=4
C(4+4-1,4-1) = C(7,3) = 35
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Refer to this post: https://www.beatthegmat.com/oranges-t70953.html#320828beat_gmat_09 wrote:If 16 oranges are distributed among 4 children such that each gets at least 3 oranges, the number of ways of distributing them is
A) 30
B) 210
C) 15
D) 35
E) 40.
Rahul Lakhani
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Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)