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OG Quant Review #102

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OG Quant Review #102

by 480ocean » Mon Feb 16, 2009 2:36 pm
I hope someone has a better way to solve this problem. The book offers a somewhat confusing solution.

Is x/m (m^2 + n^2 + k^2) = xm + yn + zk?

1. z/k = x/m
2. x/m = y/n

Answer is C

Thank you in advance!
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by Bidisha_800 » Mon Feb 16, 2009 3:28 pm
it is clear that each of these statements is not sufficient.

Rest is plain algebra.

x/m = y/n

x/m* n^2 = yn --------- (1)

z/k =x/m

z/k* K^2 = x/m* k2
zk = x/m* k2 -------------(2)

RHS = xm + yn + zk
=(x/m * m^2 )+ n^2. *x/m + x/m *k^2 (from 1 and 2)
= x/m (m^2 + n^2+ k^2)
=LHS
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