Data Sufficiency

In the expression, if xn does not equal 0, what is the value of s?

S= (2/n)/((1/x)+(2/3x))

statement 1.) x=2n

statement 2.) n=1/2

qa is a


First must simplify the given equation, which turns into s=6x/5n

so all we need is x and n in order to get value of s.

statement 1.) gives x=2n, which does prove sufficiency. HOWEVER, I am ifyou plug in numbers you will get


case (1) x= 2 n= 1

case (2) x= 6 n= 3

case (3) x= -4 n=-2


If you plug this into the equation s =6x/5n then you will get two answers. Hence insufficient. I can prove statement 1 insufficient by simply plugging in numbers. I am vehemently arguing that this statement only gives a relationship of values. With my plugged in values, I can get different values of S all day long. WHY? LEts shed some light on this!

statement 2 says nothing about x so insufficient

together, sufficient.

using all my careful math and suspicoun of tricks, I believe that I did my best here. Lets not solve this question but lets explain the ambiguity of statement 1. WHat went wrong?

simba12123 wrote:In the expression, if xn does not equal 0, what is the value of s?

S= (2/n)/((1/x)+(2/3x))

statement 1.) x=2n

statement 2.) n=1/2

qa is a

So as you get simplified expr is s=6x/5n


What do I need to solve this?
value of x and value of n
OR
value of ratio x/n

The stmt A gives me that ratio
x=2n
so x/n = 2
hence suff

First must simplify the given equation, which turns into s=6x/5n

so all we need is x and n in order to get value of s.

statement 1.) gives x=2n, which does prove sufficiency. HOWEVER, I am ifyou plug in numbers you will get


case (1) x= 2 n= 1

case (2) x= 6 n= 3

case (3) x= -4 n=-2


If you plug this into the equation s =6x/5n then you will get two answers. Hence insufficient.

What are the two values you are getting?
Please retry, all will give same value.
You must be doing some calculation mistake

I can prove statement 1 insufficient by simply plugging in numbers. I am vehemently arguing that this statement only gives a relationship of values. With my plugged in values, I can get different values of S all day long. WHY? LEts shed some light on this!

statement 2 says nothing about x so insufficient

together, sufficient.

using all my careful math and suspicoun of tricks, I believe that I did my best here. Lets not solve this question but lets explain the ambiguity of statement 1. WHat went wrong?

Hope its clear now

Success is in the details! Thank you folks. THe major takeaway is that an algebraic approach should not be looked over so easily.

Success is in the details! Thank you folks. THe major takeaway is that an algebraic approach should not be looked over so easily.