In the expression, if xn does not equal 0, what is the value of s?
S= (2/n)/((1/x)+(2/3x))
statement 1.) x=2n
statement 2.) n=1/2
qa is a
First must simplify the given equation, which turns into s=6x/5n
so all we need is x and n in order to get value of s.
statement 1.) gives x=2n, which does prove sufficiency. HOWEVER, I am ifyou plug in numbers you will get
case (1) x= 2 n= 1
case (2) x= 6 n= 3
case (3) x= -4 n=-2
If you plug this into the equation s =6x/5n then you will get two answers. Hence insufficient. I can prove statement 1 insufficient by simply plugging in numbers. I am vehemently arguing that this statement only gives a relationship of values. With my plugged in values, I can get different values of S all day long. WHY? LEts shed some light on this!
statement 2 says nothing about x so insufficient
together, sufficient.
using all my careful math and suspicoun of tricks, I believe that I did my best here. Lets not solve this question but lets explain the ambiguity of statement 1. WHat went wrong?
S= (2/n)/((1/x)+(2/3x))
statement 1.) x=2n
statement 2.) n=1/2
qa is a
First must simplify the given equation, which turns into s=6x/5n
so all we need is x and n in order to get value of s.
statement 1.) gives x=2n, which does prove sufficiency. HOWEVER, I am ifyou plug in numbers you will get
case (1) x= 2 n= 1
case (2) x= 6 n= 3
case (3) x= -4 n=-2
If you plug this into the equation s =6x/5n then you will get two answers. Hence insufficient. I can prove statement 1 insufficient by simply plugging in numbers. I am vehemently arguing that this statement only gives a relationship of values. With my plugged in values, I can get different values of S all day long. WHY? LEts shed some light on this!
statement 2 says nothing about x so insufficient
together, sufficient.
using all my careful math and suspicoun of tricks, I believe that I did my best here. Lets not solve this question but lets explain the ambiguity of statement 1. WHat went wrong?
Advancing to be reckoned with!
