Which of the following inequalities is an algebraic expression for the shaded part of the number line above?
A. |x| <= 3
B. |X| <= 5
C. |X-2| <= 3
D. |X-1|<= 4
E. |X+1|<=4
Attached the number line now
OG 12 PS 130
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- ssmiles08
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On the number line you can see that -5 <= x <= 3
you can use back solving here, from choice E.
|X+1|<=4
x + 1 <= 4
x <= 3
-|X+1|<=4
-x - 1 <= 4
-x <= 5
x >= -5
so it fits perfectly.
-5 <= x <= 3
Also, you can eliminate A and B b/c they are not closed intervals.
you can use back solving here, from choice E.
|X+1|<=4
x + 1 <= 4
x <= 3
-|X+1|<=4
-x - 1 <= 4
-x <= 5
x >= -5
so it fits perfectly.
-5 <= x <= 3
Also, you can eliminate A and B b/c they are not closed intervals.
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- Legendary Member
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reasoning way:
|x-a| is the distance from any point x to point a.
just look at the number line and see the options:
A. |x| <= 3 distance from any point to 0 is less than or equal to 3-wrong
B. |X| <= 5 distance from any point to 0 is less than or equal to 5-wrong
C. |X-2| <= 3 distance from any point to 2 is less than or equal to 3-wrong
D. |X-1|<= 4 distance from any point to 1 is less than or equal to 4-wrong
E. |X+1|<=4 distance from any point to -1 is less than or equal to 4-right
|x-a| is the distance from any point x to point a.
just look at the number line and see the options:
A. |x| <= 3 distance from any point to 0 is less than or equal to 3-wrong
B. |X| <= 5 distance from any point to 0 is less than or equal to 5-wrong
C. |X-2| <= 3 distance from any point to 2 is less than or equal to 3-wrong
D. |X-1|<= 4 distance from any point to 1 is less than or equal to 4-wrong
E. |X+1|<=4 distance from any point to -1 is less than or equal to 4-right
The powers of two are bloody impolite!!