If Z^n=1, What is the value of Z?
1) n is a non zero integer
2) Z>0
Answer is C; Someone please help me with this.
Jaheer.
OG 11, DS #126
This topic has expert replies
Hi,
let's try on this one;
Z^n = 1; many possibilities are ther.
As you know any number that is rised to 0 is equal to 1; You may also think of picking numbers to see that ; if n is odd (>0) then Z sould be 1, but if n is even (>0) then Z may be 1 or (-1); Therfore, this first stem can lead to many solutions;
1) tells that n is a non zero integer, that's fine because it eliminates the infinite possibilities of Z. , BUT this doesnt help to get a specific solution as just explained above
2) States for Z >0, we should pay attention that for Z to be equal to 1, n must be non zero inetger; which is just stated in the first option;
Thus, answer is C;
good luck
let's try on this one;
Z^n = 1; many possibilities are ther.
As you know any number that is rised to 0 is equal to 1; You may also think of picking numbers to see that ; if n is odd (>0) then Z sould be 1, but if n is even (>0) then Z may be 1 or (-1); Therfore, this first stem can lead to many solutions;
1) tells that n is a non zero integer, that's fine because it eliminates the infinite possibilities of Z. , BUT this doesnt help to get a specific solution as just explained above
2) States for Z >0, we should pay attention that for Z to be equal to 1, n must be non zero inetger; which is just stated in the first option;
Thus, answer is C;
good luck
I appologize for my Frenchy-English.
I am working on it.
I am working on it.
I understand the logic behind the answer, but I'm still a tad confused because I don't understand why z cannot be a non-integer, like the square root of 1.
IF
1) n is a nonzero integer
AND
2) z > 0
z could be the sqroot of 1
An example of this is when n = 2 (satisfying condition 1)
z = 1 (satisfying condition 2)
BUT when n = 1 (satisfying condition 1)
z = sqroot 1 (satisfying condition 1)
which would mean we could not solve for z based on this information.
Am I missing something obvious?
Thanks for your help!
IF
1) n is a nonzero integer
AND
2) z > 0
z could be the sqroot of 1
An example of this is when n = 2 (satisfying condition 1)
z = 1 (satisfying condition 2)
BUT when n = 1 (satisfying condition 1)
z = sqroot 1 (satisfying condition 1)
which would mean we could not solve for z based on this information.
Am I missing something obvious?
Thanks for your help!
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Perhaps! The positive square root of 1 is equal to 1, which maybe is the fact you're missing here. And of course, the square root of 1 is thus an integer.bcwinans wrote:I understand the logic behind the answer, but I'm still a tad confused because I don't understand why z cannot be a non-integer, like the square root of 1.
...
Am I missing something obvious?
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