OG 10 PS question #380 & #404

This topic has expert replies
Senior | Next Rank: 100 Posts
Posts: 59
Joined: Mon Mar 10, 2008 3:23 am
Thanked: 2 times
Followed by:1 members

OG 10 PS question #380 & #404

by Magellan » Thu May 01, 2008 5:45 am
Hello,

Could someone explain me reasoning behind those two questions? Problem solving from O.G., questions 380 and 404.

Thanks
Attachments
Desktop.zip
Problems 380 & 404
(20.74 KiB) Downloaded 83 times

Master | Next Rank: 500 Posts
Posts: 468
Joined: Sat Mar 03, 2007 10:17 pm
Thanked: 5 times

by moneyman » Thu May 01, 2008 8:19 am
Q 380 has already been discussed a couple of times on the forum. Please search for it.

The answer for Q 404 is (E)

(1) W=1.5 . Lets assume the area is 25 for the tiled area and 39 for the untiled one. Each side of tiled area would be 5 and the length of the side of the countertop would be 5+1.5+1.5=8. The area of the countertop would be 64 and the area of the untiled one would be 64-25=39. Satisfies the condition.

(2) W=3. Now lets assume the tiled area is 100(25*4) and the the untiled one is 156(39*4). Repeat the same procedure and you will see that the condition is satisfied.

(3) W=4.5. Tiled area = 225(25*9) and untiled area=351(39*9).Still the consition would be satisfied.

Hence (E)
Maxx