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Official question

Expert replies
Source: — Problem Solving |

by guerrero » Sun Apr 21, 2013 3:02 pm
you can solve this question by using equation--

0.6 + 0.06(x-7) = 0.08x

X= duration in minutes.

Under plan A cost is 0.6 + 0.06(x-7)

Under plan B the cost is $0.08X

since the amount needs to be equal as stated solve for X .

X=9

OA

9
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by Anju@Gurome » Sun Apr 21, 2013 6:02 pm
puneet2329 wrote:A certain phone company offers two plans A and B. Under plan A, the company charges a total of $0.6 for the first 7 minute of each call and $0.06 per minute thereafter. Under plan B the company charges $0.08 per minute of each call. What is the duration of call, in minutes, for which the company charges the same amount under plan A and under plan B?

A. 2
B. 9
C. 15
D. 21
E. 30
Algebraic Approach:
Let us assume if the duration of the call was N minutes, then the charge is same under both plans.

Now, charge under plan A = (a total of $0.6 for the first 7 minutes) + ($0.06 per minutes for (N - 7) minutes) = $0.6 + $(0.06)*(N - 7)
And, charge under plan B = $0.08 per minutes for N minutes) = $(0.08)*N

So, 0.6 + (0.06)*(N - 7) = (0.08)*N
--> 0.6 + (0.06)*N - 0.42 = (0.08)*N
--> (0.02)*N = 0.6 - 0.42 = 0.18
--> N = 0.18/0.02 = 18/2 = 9
[spoiler]
The correct answer is B.[/spoiler]
Anju Agarwal
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by Anju@Gurome » Sun Apr 21, 2013 6:08 pm
Plugging Options:
This problem can be easily solved by plugging the answer choices.

A. If the duration of the call is 2 minutes,
  • Charge under plan A = $0.6
    Charge under plan B = $(0.08)*2 = $0.16
    As the charges are not equal, option A is not the correct answer.
B. If the duration of the call is 9 minutes,
  • Charge under plan A = $0.6 for first 7 minutes + $0.06 per minutes for (9 - 7) minutes = $0.6 + $(0.06)*2 = $0.6 + $0.12 = $.72
    Charge under plan B = $(0.08)*9 = $0.72
    As the charges are same, option B is the correct answer.
As there will be only one correct answer, we don't need to check the rest of the options.
[spoiler]
The correct answer is B.[/spoiler]
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Backup Methods : General guide on plugging, estimation etc.
Wavy Curve Method : Solving complex inequalities in a matter of seconds.

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by GMATGuruNY » Sun Apr 21, 2013 6:13 pm
A certain telephone company offers two plans, A and B. Under plan A, the company charges a total of $0.60 for the first 7 minutes of each call and $0.06 per minute thereafter. Under plan B, the company charges $0.08 per minute of each call. What is the duration of a call, in minutes, for which the company charges the same amount under plan A and under plan B?

A. 2
B. 9
C. 15
D. 21
E. 30
Under plan A, the cost of the first 7 minutes = 60 cents.
Since plan B charges 8 cents per minute, the cost of the first 7 minutes under plan B = 7*8 = 56 cents.
Plan B needs to catch up by 4 cents.

We can plug in the answers, which represent the total time required for the two plans to charge the same amount.
After the first 7 minutes, the difference between plan B's rate and plan A's rate = 8-6 = 2 cents per minute.
Since plan B is behind plan A by only 4 cents, it will not take long for plan B to catch up to plan B.
Thus, answer choice B -- which implies that only 2 additional minutes are needed -- seems almost certain to be correct.

Answer choice B: 7 minutes + 2 additional minutes
Total cost for plan A = 60 + 2(6) = 72.
Total cost for plan B = 56 + 2(8) = 72.
Success!

The correct answer is B.
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