Data Sufficiency

Of the 60 families in a certain neighborhood, 38 have a cat. How many of the families in this neighborhood have a dog?

(1) 28 of the families in this neighborhood have a cat but not a dog
(2) The number of families in the neighborhood who have a dog and a cat is the same as the number of families who have neither a cat nor a dog.

OA B

I have found that statement 1 alone is insufficient.

I am facing problem regarding calculation in statement B even though I know that statement 2 alone is sufficient.

Kindly see my calculation thoroughly and let me know where I am doing mistake.

I have solved this in matrix form.

Please find the attachment

I found the number of the families in this neighborhood have a dog which is 22(highlighted in yellow)through this way. So I found statement 2 is sufficient.


When I am calculating this below way I also able to find the answer:

D = no of the families have a dog.

60 = 38+D-X+X
or, D = 22.

But my problem is when I am solving this below way I am not able to solve X.

60 = 38-X+X+X+22-X (refer my above matrix in order to find how I got this expression)

Then I do not know how to solve.

I know I am doing here some mistake. Please point out my mistake in this calculation.