What are the first six digits of 1/9+1/99+1/999, if expressed as a decimal?
a .122123
b .122213
c .123123
d .123212
e .123321
a .122123
b .122213
c .123123
d .123212
e .123321
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a/9 = 0.aaaaa...kop wrote:What are the first six digits of 1/9+1/99+1/999, if expressed as a decimal?
a .122123
b .122213
c .123123
d .123212
e .123321
1/9 =0 .111111kop wrote:What are the first six digits of 1/9+1/99+1/999, if expressed as a decimal?
a .122123
b .122213
c .123123
d .123212
e .123321
Hi,Mathsbuddy wrote:In the answer list the 1st 2 digits are all the same, so we only need to consider the 3rd and 4th digits to identify which is correct.
Knowing:
1/9 -> decimal positions of 1 are multiples of 1
1/99 -> decimal positions of 1 are multiples of 2
1/999 -> decimal positions of 1 are multiples of 3
gives us (3rd, 4th) digits of (1+1, 1+1) = (2,2)
Therefore answer B.