BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

numbers

Expert replies
by vaivish » Wed Jun 25, 2008 8:35 am
If 5 numbers are selected from 1, 2, 3, ...10, without replacement, what is the greatest possible value that the average of five numbers is greater than the median of five numbers?
(A) 1
(B) 3/2
(C) 2
(D) 5/3
(E) 3
Join the discussion
Source: — Problem Solving |

by atlantic » Wed Jun 25, 2008 9:58 am
Vavish,

I believe that the text is not correctly transcript.

Although, according to was is written the answer is C.

Lets see how.....

From 1,2,3,.....,10 you have to chose a serie of five that gives the greater possible mean but the least median and that can only be...

{1,2,3,9,10}, why? because it minimize the median (=3) and chosing the numbers 9 and 10 we can only maximize the mean (=5).

So 5-3=2

Hope it helps
Join the discussion

by vaivish » Wed Jun 25, 2008 11:01 am
no i still dont understand...can you explain...[/quote]
Join the discussion

by Carol » Wed Jun 25, 2008 12:41 pm
We know to find the median you have to reorder the numbers from least to greatest and pick the middle number - {1,2,3,9,10}

What about 9 and 10? because you're asked to find the mean (average) bigger than the median (in this case, bigger than 3).

Mean = 1+2+3+9+10/5 = 5.

If you find the difference between both average and median

5-3=2.
Join the discussion

by atlantic » Wed Jun 25, 2008 1:00 pm
Thanks for help me with my reasoning, Carol.
Join the discussion