P and N are natural numbers. If P^N has the same unit's digit as P, how many possibilities exist for the unit's digit of P?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Would like to know the methodology. OA is D
Number System
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the digits are 0,1,5,6 = 4(d)CaptainHaddock wrote:P and N are natural numbers. If P^N has the same unit's digit as P, how many possibilities exist for the unit's digit of P?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Would like to know the methodology. OA is D
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Well I have a concern here-CaptainHaddock wrote:P and N are natural numbers. If P^N has the same unit's digit as P, how many possibilities exist for the unit's digit of P?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
Would like to know the methodology. OA is D
1) what is the source of this question?
2) I can give you many more examples in addition to 1,5,6, and 0.
For example if p =3 and N = 5 then 3^5 = 243. this also satisfies the given condition.
If p= 7 and N= 5 then 7^5 = 16807. this also satisfies the given condition.
NONE OF THE OPTIONS SATISFY THIS CONDITION
Again, what is the source of this question?
NONE OF THE OPTIONS SATISFY THIS CONDITION
- sam2304
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D is right.
P can take any value and N can take any value
only numbers ending with 0, 1, 5, 6 raised to power of N will have same unit's digit as P
P can take any value and N can take any value
only numbers ending with 0, 1, 5, 6 raised to power of N will have same unit's digit as P
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