BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Number Properties

Expert replies
by raju232007 » Mon Jan 25, 2010 2:10 am
The answer to this question has already been posted in this forum..But I am still not able to understand the explanation

If x and y are integers and x>0, is y>0?
1. 7x-2y>0
2. -y<x

The first statement says that 7x-2y>0........................(1)
The second statement can be rewritten as x+y>0..
Multiplying by 7 on both sides we get 7x+7y>0 ..........(2)

(1) - (2) gives -9y>0 .....From this equation we can clearly observe that y is negative..
So in my opinion the answer to this question should be C..

But the OA is E...Could someone point out where I am going wrong?
Join the discussion
Source: — Data Sufficiency |

by ajith » Mon Jan 25, 2010 2:24 am
raju232007 wrote:The answer to this question has already been posted in this forum..But I am still not able to understand the explanation

If x and y are integers and x>0, is y>0?
1. 7x-2y>0
2. -y<x

The first statement says that 7x-2y>0........................(1)
The second statement can be rewritten as x+y>0..
Multiplying by 7 on both sides we get 7x+7y>0 ..........(2)

(1) - (2) gives -9y>0 .....From this equation we can clearly observe that y is negative..
So in my opinion the answer to this question should be C..

But the OA is E...Could someone point out where I am going wrong?
You cannot deduct one inequality from another. You can only add them as long as they have similar signs in the middle

-(2) gives -7x - 7y <0 ---(3) ( if you multiply an en equality by a negative number the sign changes)

Now the (1) and (3) cannot be added since one is a greater than and the other is a less than inequality

that's where you are going wrong
Last edited by ajith on Mon Jan 25, 2010 3:33 am, edited 1 time in total.
Always borrow money from a pessimist, he doesn't expect to be paid back.
Join the discussion

by raju232007 » Mon Jan 25, 2010 2:56 am
Thanks for your prompt response....But why can't -7x-7y<0 be multiplied by -1 on both sides to give 7x+7y>0?
Join the discussion

by ajith » Mon Jan 25, 2010 3:16 am
raju232007 wrote:Thanks for your prompt response....But why can't -7x-7y<0 be multiplied by -1 on both sides to give 7x+7y>0?
You can do that and it is perfectly valid.
Always borrow money from a pessimist, he doesn't expect to be paid back.
Join the discussion

by raju232007 » Mon Jan 25, 2010 3:25 am
I am sorry to if bother you again.....but then if 7x+7y>0 is fine then I can combine this equation with equation 1 (i.e 7x-2y>0) to conclude that -9y>0, so y should be negative...
That is

7x-2y>0..............(1)
7x+7y>0.............(2)

(1)-(2) => -9y>0


Can you tell me what's wrong in what I have done?
Join the discussion

by ajith » Mon Jan 25, 2010 3:31 am
raju232007 wrote:I am sorry to if bother you again.....but then if 7x+7y>0 is fine then I can combine this equation with equation 1 (i.e 7x-2y>0) to conclude that -9y>0, so y should be negative...
That is

7x-2y>0..............(1)
7x+7y>0.............(2)

(1)-(2) => -9y>0


Can you tell me what's wrong in what I have done?
Only add operation is valid for inequalities ( Signs have to match)

(1) + (2) is valid operation since - inequalities have the same sign

(1) - (2) is not a valid operation (because it is nothing but (1) + (-(2)) and signs do not match there)

Further I will make it obvious by an example

say x = 1 and y =1

Follows (1) and (2)

since 5>0 and 14>0

Now if we follow your math

y<0 but y =1 which is greater than 0.
Always borrow money from a pessimist, he doesn't expect to be paid back.
Join the discussion