Data Sufficiency

If x and y are nonzero, is (x^3)(y^5)/(x^2)(y^3)>0
1). x>0
2). y>0

If x and y are nonzero, is (x^3)(y^5)/(x^2)(y^3)>0
The question can be rephrased to
Is x*(y^2)>0 ?

1). x>0

y^2 > 0
x > 0
x*(y^2)>0
Sufficient

2). y>0

y^2 > 0
x ??
Insufficient

IMO A

sud21 wrote:If x and y are nonzero, is (x^3)(y^5)/(x^2)(y^3)>0
1). x>0
2). y>0

1. Let y<0, then

(positive)(negative) / (positive)(negative) = positive

Let y>0, then

(positive)(positive) / (positive)(positive) = positive

SUFFICIENT

2. Let x < 0, then

(negative)(positive) / (positive)(positive) = negative

Let x > 0, then

(positive)(positive) / (positive)(positive) = positive

INSUFFICIENT



ANSWER A